Failed to open stream? Image upload but are not echoing

debugcn Published at Dev

Rebecca Joanna

I am working on upload file in php. i done it successfully but when i want to print it it give me error plz help me My php Script is below

<?php
$target_dir = "C:\wamp\www\upload\upload/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);

if(isset($_POST["submit"])) {
    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        echo "File is not an image.";
        $uploadOk = 0;
    }
}

if (file_exists($target_file)) {
    echo "Sorry, file already exists.";
    $uploadOk = 0;
}

if ($_FILES["fileToUpload"]["size"] > 500000) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}

if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
    echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
    $uploadOk = 0;
}

if ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";

} else {
    if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
        echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
	
	if(copy($_FILES['fileToUpload']['name'], $target_dir))
{
echo "Successful<BR/>";
echo "File Name :".$_FILES['fileToUpload']['name']."<BR/>";
echo "File Size :".$_FILES['fileToUpload']['size']."<BR/>";
echo "File Type :".$_FILES['fileToUpload']['type']."<BR/>";
echo "<img src=\"$target_dir\" width=\"150\" height=\"150\">";
}
}
?>

following error occur

it should be print like this once it uploaded enter link description here

Masroor_Shah

TRy like this

	if (is_file($target_file))
{
echo "Successful<BR/>";
echo "File Name :".$_FILES['fileToUpload']['name']."<BR/>";
echo "File Size :".$_FILES['fileToUpload']['size']."<BR/>";
echo "File Type :".$_FILES['fileToUpload']['type']."<BR/>";
echo "<img src=\"$target_file\" width=\"150\" height=\"150\">";
}

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