I'm working on a program that determines a type of torus, volume of that torus, surface area, and cost of fabricating it/painting it based upon 2 input radii: rmajor and rminor. The only complicated part is I can't use logical operators or comparison statements. I am able to determine the surface area, volume, and costs related to the torus but I can't determine the manufacturing code (as shown in the print statements). The corresponding Manufacturing codes are as follows:
How would I go about correctly printing the corresponding manufacturing code to each type of torus?
Here is my current code:
#include<stdio.h>
#include<math.h>
//GLOABAL DECLARATIONS
#define COST 75.25
#define PAINT 13.65
int main()
{
//LOCAL DECLARATIONS
int rmajor;
int rminor;
int factor1;
int factor2;
int factor3;
char char1;
char char2;
double area;
double volume;
double cost;
double paint;
//EXECUTABLES
printf("Please input major radius (meters): ");
scanf("%d" , &rmajor);
printf("Please input minor radius (meters): ");
scanf("%d", &rminor);
printf("\n=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=\n");
volume = (M_PI * pow(rminor,2)) * (2*M_PI*rmajor);
area = (4 * pow(M_PI,2) * rmajor * rminor);
factor1 = rmajor / rminor;
factor2 = rminor / rmajor;
factor1 = (factor1 + 2) % (factor1 + 1);
factor2 = (factor2 + 2) % (factor2 + 1);
factor3 = (factor1 * rmajor) + (factor2 * rminor);
factor3 = factor3 / (factor1 + factor2);
char1 = (factor1 * ('R' - 'A')) + (factor2 * ('H' - 'A')) + (factor3 * ('S' - 'A'));
char2 = (factor1 * ('i' - 'A')) + (factor2 * ('n' - 'A')) + (factor3 * ('p' - 'A'));
//printf("\nchar1: %c\n", char1);
//printf("char2: %c\n", char2);
cost = COST * volume;
paint = PAINT * area;
printf("Manufacturing Code: %c%c\n ", 'A' + char1, 'A' + char2);
printf("Surface Area : %13.2f\n", area);
printf("Volume : %13.2f\n", volume);
printf("=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-\n");
printf("Cost of building torus ($): %12.2f\n", cost);
printf("Cost of painting torus ($): %12.2f\n", paint);
printf("=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-\n");
return(0);
}
Here are some of my example outputs:
Please input major radius (meters): 10
Please input minor radius (meters): 5
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Manufacturing Code: ?
Surface Area : 1973.92
Volume : 4934.80
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
Cost of building torus ($): 371343.87
Cost of painting torus ($): 26944.02
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
52 lpvinslogin01.itap.purdue.edu ~/CS159/labs/lab03 % a.out
Please input major radius (meters): 7
Please input minor radius (meters): 7
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Manufacturing Code: ▒▒
Surface Area : 1934.44
Volume : 6770.55
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
Cost of building torus ($): 509483.78
Cost of painting torus ($): 26405.14
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
Output 1 is supposed to be a ring torus (Ri) and Output 2 should be a horn torus (Hn). Any help is appreciated, thank you!
Your code computes factor1 and factor2 incorrectly: they stay 1 when the values are equal, while multiplication inside the computation of char1 and char2 suggests that exactly one of factor1, factor2, and factor3 must be 1, and the remaining ones must be zero.
You can fix this problem by multiplying factor1 and factor2 by (factor3+1)%2:
factor1 = rmajor / rminor;
factor2 = rminor / rmajor;
factor1 = (factor1 + 2) % (factor1 + 1);
factor2 = (factor2 + 2) % (factor2 + 1);
factor3 = (factor1 * factor2); // rmajor == rminor
factor1 *= (factor3+1) % 2; // rmajor > rminor
factor2 *= (factor3+1) % 2; // rmajor < rminor
char1 = (factor1 * 'R') + (factor2 * 'S') + (factor3 * 'H');
char2 = (factor1 * 'i') + (factor2 * 'p') + (factor3 * 'n');
printf("Manufacturing Code: %c%c\n ", char1, char2);
Note that factoring out 'A' from the computation lets you arrive at a much simpler forumla.
Demo.
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