And again about calculate the number of days between two dates using JavaScript

debugcn Published at Dev

Vitaly

Seems that solution from How to calculate the number of days between two dates using JavaScript? work fine exept for case : 30.4.2016 - 1.5.2016 it calculate 2 days ( in real 1 ) 29.2.2016 - 1.3.2016 it calculate 3 days ( in real 1 )

May be someone already found solution for these cases ?

This function from link
function count_days(){ // Expecting resuls: positive when date1 > date2  ; negative  when date1 < date2  
            var $obj = "dd.mm.YYYY";
            var $obj2 = "dd.mm.YYYY";
            if($obj2.value){
                $start=$obj.value.split(".");
                var date1 = new Date($start[2],$start[1],$start[0]); // Converted date to ("YYYY,mm,dd")
                var $stop=$obj2.value.split(".");
                var date2 = new Date($stop[2],$stop[1],$stop[0]); // Converted date to ("YYYY,mm,dd")
                var oneDay = 24*60*60*1000; // hours*minutes*seconds*milliseconds
                var diffDays = (date2.getTime() - date1.getTime())/(oneDay);
                if(diffDays >= 0){
                    return Math.abs(diffDays)+1;
                } else {
                    return diffDays-1;
                }
            }
return false; // No date2 nothing to compare  
}
// Expecting resuls in full days (24h):  
//(5.5.2016 - 5.5.2016) =  1 day (days equal)  
//(29.2.2016 - 1.3.2016) =  1 day  
//(30.4.2016 - 1.5.2016) =  1 day  
//(4.5.2016 - 5.5.2016) =  2 days  
//(29.2.2016 - null) = False   
//(1.3.2016 - 29.2.2016) = -1 day  
//(1.5.2016 - 30.4.2016) = -1 day  
//(5.5.2016 - 4.5.2016)  = -2 day

Vitaly

Finaly good working code

function count_days(){ 
            var $obj = "dd.mm.YYYY";
            var $obj2 = "dd.mm.YYYY";
            if($obj2.value){
                $start=$obj.value.split(".");
                var date1 = new Date($start[2],$start[1]-1,$start[0]); // Converted date to ("YYYY,mm,dd")
                var $stop=$obj2.value.split(".");
                var date2 = new Date($stop[2],$stop[1]-1,$stop[0]); // Converted date to ("YYYY,mm,dd")
                var oneDay = 24*60*60*1000; // hours*minutes*seconds*milliseconds
                var diffDays = (date2.getTime() - date1.getTime())/(oneDay);
                if(diffDays >= 0){
                    return Math.abs(diffDays)+1; // positive as date1 > date2    
                } else {
                    return diffDays-1;  //negative  as date1 < date2
                }
            }
return false; // No date2 nothing to compare  
}

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