I am trying to upgrade Java with a batch file, and I need to change the PATH system variable to reflect that change. At the beginning of the PATH variable I have
C:\Program Files\Java\jdk1.8.0_51;...
I need to change the jdk value to be jdk1.8.0_60. I'm relatively new to command line and batch files, and so I may be misunderstanding something. Here is what I am trying.
I have a couple variables
jVersion=1.8.0_
javaPath=C:\Program Files\Java
newVersion=60
oldVersion=51
I found something about replacing strings with literal values like so
set PATH=%PATH:1.8.0_51=1.8.0_60%
but I can't get it to work with variables...
set PATH=%%PATH:%jVersion%%oldVersion%=%jVersion%%newVersion%%%
I don't know if you need 2 %'s around the outside, or just one, or !'s. I'm not super confident in my knowledge of delayed expansion. I also don't know if this is possible.
As a bonus, I would really like to be able to take whatever comes after ...\Java\ and replace it with my new value. This would be just in case I don't know the value in the PATH variable for the jdk
Thanks!
EDIT: By using the command call before a modified version of my code I was able to get it to work
call set PATH=%PATH:%jVersion%%oldVersion%=%jVersion%%newVersion%%
I'm still trying to figure out how to make it generic and change whatever comes after ...\jdk to the values I have.
paste the Below Code in a bat file and that should solve the problem
@echo off
setlocal EnableDelayedExpansion
set jVersion=1.8.0_
set "javaPath=C:\Program Files\Java"
set newVersion=60
set oldVersion=51
set PATH=%jVersion%%oldVersion%
echo before path change : !PATH!
set PATH=!PATH:%jVersion%%oldVersion%=%jVersion%%newVersion%!
echo final path change : !PATH!
pause
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