I have a variable set with var='type_cardio_10-11-2017'. I need to remove the last 10 letters from the variable, and append the remaining value to var2.
I tried with the following script, but it doesn't work as expected.
var=type_cardio_10-11-2017
var2=${var} | cut -f1 -d "_"
echo ${var2}
The output I want is type_cardio.
To remove everything from after the last _ in var and assign the result to var2:
var2=${var%_*}
The parameter expansion ${parameter%word} removes the pattern word (_* in this case) from the end of the value of the given variable.
The POSIX standard calls this a "Remove Smallest Suffix Pattern" parameter expansion.
To remove the last underscore and the 10 characters after it, use
var2=${var%_??????????}
To remove characters corresponding to a date string such as the one in your example, use
var2=${var%_[0-9][0-9]-[0-9][0-9]-[0-9][0-9][0-9][0-9]}
Which pattern you use depends on how carefully you want to perform the match.
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