How to number each line in the output using a for loop?

debugcn Published at Dev

Mona Ramesh

import java.util.Scanner;

public class LoveCS
{
    public static void main(String[] args) 
    {
        int noTimesPrinted;

        Scanner scan = new Scanner(System.in);

        System.out.print("How many times should the message be printed: ");
        noTimesPrinted = scan.nextInt();

        int count = 1;
        while (count <= noTimesPrinted) 
        {
            System.out.println(" I love Computer Science!!");
            count++;
        }
    }
}

Instead of using constant LIMIT, ask the user how many times the message should be printed. You will need to declare a variable to store the user’s response and use that variable to control the loop. (Remember that all caps is used only for constants!)

I HAVE COMPLETED PART1. I AM STUCK ON PART2. How do I get the number sequence??

Number each line in the output, and add a message at the end of the loop that says how many times the message was printed. So if the user enters 3, your program should print this:
```
 1 I love Computer Science!!
 2 I love Computer Science!!
 3 I love Computer Science!!
 Printed this message 3 times.
```
If the message is printed N times, compute and print the sum of the numbers from 1 to N. So for the example above, the last line would now read:
```
Printed this message 3 times. The sum of the numbers from 1 to 3 is 6.
```
Note that you will need to add a variable to hold the sum.

Elliott Frisch

You have a few choices. You could use String concatenation,

int count = 1;
while (count <= noTimesPrinted) 
{
    System.out.println(Integer.toString(count) + " I love Computer Science!!");
    count++;
}
System.out.println("Printed this message " + noTimesPrinted + " times");

Or with printf and (since you said you wanted a for loop) something like

for (int count = 1; count <= noTimesPrinted; count++) {
    System.out.printf("%d I love Computer Science!!%n", count);
}
System.out.printf("Printed this message %d times%n", noTimesPrinted);

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