I have came across this script:
#! /bin/bash
if (( $# < 3 )); then
echo "$0 old_string new_string file [file...]"
exit 0
else
ostr="$1"; shift
nstr="$1"; shift
fi
echo "Replacing \"$ostr\" with \"$nstr\""
for file in $@; do
if [ -f $file ]; then
echo "Working with: $file"
eval "sed 's/"$ostr"/"$nstr"/g' $file" > $file.tmp
mv $file.tmp $file
fi
done
What is the meaning of the lines where they use shift? I presume the script should be used with at least arguments so...?
shift is a bash built-in which kind of removes arguments from the beginning of the argument list. Given that the 3 arguments provided to the script are available in $1, $2, $3, then a call to shift will make $2 the new $1. A shift 2 will shift by two making new $1 the old $3. For more information, see here:
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