Say I have a list x = [1, 2, 3, 4, 5, 3, 4]
Is there any recursive method to find if the element a (let's say a = 3) is in the list using only the condition if not x: and the instruction list.pop([i])?
def rec(lista, goal):
if not lista:
return False
return (goal==lista.pop() or rec(lista, goal))
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