I have a form, like this:
echo '<table align=center border=1>';
echo '<form method="post">';
echo '<tr>';
echo '<th>Lista Echipamente</th>';
echo '<th>Actiune</th>';
echo '</tr>';
while($row=mysql_fetch_array($sql)){
echo '<tr>';
echo '<td><input class="search-logi" id="tip" type="text" name="tip" value="'.$row['tip'].'"></td>';
echo '<td><input type=submit name=modifica value=Modifica></td>';
echo '</tr>';
}
echo '</form>';
echo '</table>';
Because of the loop, this form will have multiple rows. For each input, will be a button. Lets say I want to add a value in the second input, then I will submit it (also the second button, obviously). Here comes the problem, in my code I have just a button, but the user see as many as the loop goes. How can I check which button is submitted?
Alternatively, you could utilize <button> tags for this purpose:
echo '<form method="post">'; // form tags are outside to be valid!!!
echo '<table align=center border=1>';
echo '<tr>';
echo '<th>Lista Echipamente</th>';
echo '<th>Actiune</th>';
echo '</tr>';
while($row = mysql_fetch_assoc($sql)){
echo '<tr>';
echo '<td><input class="search-logi" type="text" name="tip['.$row['id'].']" value="'.$row['tip'].'"></td>';
echo '<td><button type="submit" name="modifica" value="'.$row['id'].'">Modifica</button</td>';
echo '</tr>';
}
echo '</table>';
echo '</form>';
Then on the processing form:
$modifica = $_POST['modifica']; // shoud return the index num
$tip = $_POST['tip'][$modifica]; // select which textbox
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