I am implementing color picker using the library from AmbilWarna, with alpha being turned on.
Sample code is as follows: https://code.google.com/p/android-color-picker/
While a color code is returned,
I would like to use these returned color code to set the background color of the buttons. How could these color codes be interpreted? And why are some being negative? Is it necessary to convert to RGB codes?
All values are in decimal.
white with 100% transparency: color code = 16777215
16777215(10) = FFFFFF(16)
You need not convert this, you can directly set this.
myView.setBackgroundColor(value);
If you have HEX value ex "#FFFFFF", we have to set as
myView.setBackgroundColor (Color.parseColor ("#FFFFFF"));
Color.parseColor ("#FFFFFF"); is called, which inturn returns int
The below method is copied from android.graphics.Color.java
/**
* Parse the color string, and return the corresponding color-int.
* If the string cannot be parsed, throws an IllegalArgumentException
* exception. Supported formats are:
* #RRGGBB
* #AARRGGBB
* 'red', 'blue', 'green', 'black', 'white', 'gray', 'cyan', 'magenta',
* 'yellow', 'lightgray', 'darkgray', 'grey', 'lightgrey', 'darkgrey',
* 'aqua', 'fuschia', 'lime', 'maroon', 'navy', 'olive', 'purple',
* 'silver', 'teal'
*/
public static int parseColor(String colorString) {
if (colorString.charAt(0) == '#') {
// Use a long to avoid rollovers on #ffXXXXXX
long color = Long.parseLong(colorString.substring(1), 16);
if (colorString.length() == 7) {
// Set the alpha value
color |= 0x00000000ff000000;
} else if (colorString.length() != 9) {
throw new IllegalArgumentException("Unknown color");
}
return (int)color;
} else {
Integer color = sColorNameMap.get(colorString.toLowerCase(Locale.ROOT));
if (color != null) {
return color;
}
}
throw new IllegalArgumentException("Unknown color");
}
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