Consider the following code:
#include <iostream>
int main()
{
int index;
std::cin >> index;
int* dynArray = new int[5];
dynArray[index] = 1;
int stackArray[5];
stackArray[index] = 1;
}
I know for sure that dynArray is a simple int* pointer and it takes additional sizeof(int*) bytes on stack.
Question 1: Is an additional pointer variable also created on stack for stackArray? If so, does that always happen? If not, then how does stackArray[index] = 1; work without knowing array base, i.e. how does the compiler decide what value to add to index for calculating address?
Question 2: Is there any difference between C/C++?
I want an answer for these 2 environments:
stackArray is an array, not a pointer. Its type is int[5], i.e., an array of 5 integers. The compiler knows the type of elements of the array which is int. stackArray[index] is evaluated to *(stackArray + index). Here, the array stackArray evaluates to a pointer to its first element.
C and C++ are same in terms of an array which has automatic storage allocation.
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