I have 4 buttons. Once on the page, I only want button 1 to show. Once button 1 has been clicked, it disappears and only button 2 is visible. Once button 2 has been clicked, it disappears and only button 3 shows. The same thing happens for button 5. Any help would be appreciated.
<html>
<script>
function enableButton2() {
document.getElementById("button2").disabled = false;
}
function enableButton3() {
document.getElementById("button3").disabled = false;
}
function enableButton4() {
document.getElementById("button4").disabled = false;
}
function enableButton5() {
document.getElementById("button5").disabled = false;
}
</script>
</head>
<body>
<input type="button" id="button1" value="button 1" onclick="enableButton2()"
onclick="hidden" />
<input type="button" id="button2" value="button 2" disabled onclick="enableButton3()"
onclick="hidden" />
<input type="button" id="button3" value="button 3" disabled
onclick="enableButton4()" onclick="hidden" />
<input type="button" id="button4" value="button 4" disabled onclick="enableButton5()"
onclick="hidden" />
There's no need for a different function for each button. Make the ID of the next button a parameter of a single function. And to hide the first button, you need to set its display style, so pass this as another argument.
HTML:
<input type="button" id="button1" value="button 1" onclick="enableButton(this, 'button2')" />
<input type="button" id="button2" value="button 2" disabled onclick="enableButton(this, 'button3')" />
<input type="button" id="button3" value="button 3" disabled onclick="enableButton(this, 'button4')" />
...
JS:
function enableButton(thisButton, nextButton) {
thisButton.style.display = "none";
document.getElementById(nextButton).disabled = false;
}
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