Copy node and alter its content

debugcn Published at Dev

SnoWhite

I'm kinda stuck on a transformation i'd like to make on a xml file.

Basically i'm trying to copy all the xml but change some tags which only begins like this

XML code :

<test alt="foo" title="bar"/>

What i'd like to get after passing the xsl :

<test alt="foo"/>

<change alt="foo" title=""/>

Thing is, sometimes i got tag with a lot of attributes, so i dont want to make a template match and then change every attributes manually.

Actually i'm doing this :

<xsl:template match="test">
    <change><xsl:apply-templates select="@*|node()"/></change>
</xsl:template>

<xsl:template match="test/@title">
    <xsl:attribute name="title">
        <xsl:value-of select=""/>
    </xsl:attribute>
</xsl:template>

But it doesnt change the content of title in the output.

Martin Honnen

For all such tasks you should start with the identity transformation template

<xsl:template match="@* | node()">
  <xsl:copy>
    <xsl:apply-templates select="@* | node()"/>
  </xsl:copy>
</xsl:template>

and then add templates for nodes that need special treatment, for instance

<xsl:template match="@* | node()">
  <xsl:copy>
    <xsl:apply-templates select="@* | node()"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="test/@title"/>

would copy everything unchanged but would delete all title attributes of test elements.

    <xsl:template match="@* | node()">
      <xsl:copy>
        <xsl:apply-templates select="@* | node()"/>
      </xsl:copy>
    </xsl:template>

<xsl:template match="test">
    <change><xsl:apply-templates select="@*|node()"/></change>
</xsl:template>

<xsl:template match="test/@title">
    <xsl:attribute name="title"/>
</xsl:template>

should implement your second requirement. If you still have problems then post minimal but complete samples allowing us to reproduce the problem.

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