Changing integer bits

Ok, I have N = integer, P = position,V = 0 or 1 I have to change the bit at position P of integer N with the value V
I'm trying with
N = 5 (101)
P = 2 (takes the 1)
V = 0 (has to make it a zero)
and the result is 97 (1100 0001) (should be 0000 0001) I think the problem is from the mask because when I write it in the console its -5 (as it should be) but if I parse it, to see its bits I get an error (overflow)
the program is in the making so I'm currently working on V = 0 so don't try with 1
Yesterday I posted a question and a lot of people posted sh*t like "this is not a question - you want us to solve u your problem"
- No, I don't want you to solve me the problem I want to know why after int result = mask & integerBinary; I get 97 and not 1

using System;
class ChangeBit
{
    static void Main()
    {
        Console.Write("(n) Type an integer: ");
        string integerLine = Console.ReadLine(); // Read string from console
        Console.Write("(p) Type position: ");
        string positionLine = Console.ReadLine(); // Read string from console
        Console.Write("(v) Type 0 or 1: ");
        string valueLine = Console.ReadLine(); // Read string from console
        int value;
        int integer;
        int position;
        if (int.TryParse(integerLine, out integer) && int.TryParse(positionLine, out position) && int.TryParse(valueLine, out value)) // Try to parse the strings as integers
        {
            int integerBinary = int.Parse(Convert.ToString(integer, 2));
            int bitValue = ((1 << position) & integerBinary) >> position;
            int mask = ~(1 << position);
            if (value==0)
            {
            int result = mask & integerBinary;
            Console.WriteLine("(n) After bit conversion = {0}", result);
            }
            else Console.WriteLine("(n) After bit conversion = {0}", integer);
        }
        else
        {
        Console.WriteLine("Invalid input.");
       }
    }
}