Looking for a way to invoke more than one command in a xargs one-liner, I found the recommendation in findutils to invoke the shell from xargs like this:
$ find ... | xargs sh -c 'command $@'
The funny thing is, if I use xargs like that, for some reason it skips the first argument:
$ seq 10 | xargs bash -c 'echo $@'
2 3 4 5 6 7 8 9 10
$ seq 10 | xargs -n2 bash -c 'echo $@'
2
4
6
8
10
Is something wrong with my shell or xargs version? Is that documentation inaccurate?
Using xargs (GNU findutils) 4.4.2 and GNU bash, version 4.3.11(1)-release.
The [bash] man page says: "-c string If the -c option is present, then commands are read from string. If there are arguments after the string, they are assigned to the positional parameters, starting with $0." - The key is $0; it means that the command name shall be the first argument.
seq 10 | xargs sh -c 'echo $@; echo $0' sh
1 2 3 4 5 6 7 8 9 10
sh
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