This line ran in a script
su --session-command="$javaCommandLine & >>$serviceLogFile 2>&1 & echo \$! >$pidFile" $serviceUser || return 1
pid="$(<$pidFile)"
echo $pid
The Pid is increased by one from the Pid the program ran by su really is.
How I do I get that program's pid?
I got a answer from serverfault stackexchange. by Daniel t. @ https://serverfault.com/questions/563087/sh-bash-script-ambiguous-redirect-pid-of-file-using-single-quotes
Quoted:
The process ID is off by one because you have put an extra
&after the$javaCommandLine. In other words, you have put two processes in the background before callingecho $!, thus getting the PID of>>$serviceLogFile 2>&1rather than$javaCommandLine. Those two pieces should be put in one, as the old 2 line codes showssu --session-command="$javaCommandLine & >>$serviceLogFile 2>&1 & echo \$! >$pidFile" $serviceUser || return 1You might need to change it to -
su --session-command="$javaCommandLine >>$serviceLogFile 2>&1 & echo \$! >$pidFile" $serviceUser || return 1
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