I am currently doing this:
if x in a and y in a and z in a and q in a and r in a and s in a:
print b
Is there a more pythonic way to express this if statement?
Using the all function allows to write this in a nice and compact way:
if all(i in a for i in (x, y, z, q, r, s)):
print b
This code should do almost exactly the same as your example, even if the objects are not hashable or if the a object has some funny __contains__ method. The all function also has similar short-circuit behavior as the chain of and in the original problem. Collecting all objects to be tested in a tuple (or a list) will guarantee the same order of execution of the tests as in the original problem. If you use a set, the order might be random.
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