Given:
#[repr(u16)]
#[derive(PartialEq, Debug, Eq, Hash, Clone)]
pub enum SomeEnum {
SomeValue1 = 1,
SomeValue2 = 1 << 2 | Self::SomeValue1 as u16, // some bitmasks
// ...
}
pub fn some_check(actual_value_ref: &SomeEnum, base_value: SomeEnum) -> bool {
let actual_value_u16 = actual_value_ref.clone() as u16; // how to cast without cloning?
let base_value_u16 = base_value as u16;
actual_value_u16 & base_value_u16 == base_value_u16 // bitmask operation
}
How one can get value by reference for a primitive without explicit cloning? Cloning of u16 does not look like a tragedy but what's the right way to do it? Since enum is explicitly marked as #[repr(u16)] why compiler doesn't do it out-of-box?
To avoid explicit cloneing, I think it should suffice to derive(Copy) for SomeEnum.
Collected from the Internet
Please contact [email protected] to delete if infringement.
Comments