如何拆分任何URL并仅获取源代码？

Shahariar Rahman Sajib 发表于 Dev

沙哈里亚·拉赫曼·萨吉布（Shahariar Rahman Sajib）

我想分割https://abcnews.go.com/这种类型的URL。

想要获得abcnews

我用了：

.split('//')[1]
.split('www.')[1]
.split('.com')[0]
.split('.org')[0]
.split('.edu')[0]
.split('.info')[0]

我得到错误无法拆分。

知道怎么做吗？

理查德·捷克

这看起来很安全：

(?:https?:\/\/(?:www\.)?|www\.)([^.\/]+)

见证明。

解释

--------------------------------------------------------------------------------
  (?:                      group, but do not capture:
--------------------------------------------------------------------------------
    http                     'http'
--------------------------------------------------------------------------------
    s?                       's' (optional (matching the most amount
                             possible))
--------------------------------------------------------------------------------
    :                        ':'
--------------------------------------------------------------------------------
    \/                       '/'
--------------------------------------------------------------------------------
    \/                       '/'
--------------------------------------------------------------------------------
    (?:                      group, but do not capture (optional
                             (matching the most amount possible)):
--------------------------------------------------------------------------------
      www                      'www'
--------------------------------------------------------------------------------
      \.                       '.'
--------------------------------------------------------------------------------
    )?                       end of grouping
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    www                      'www'
--------------------------------------------------------------------------------
    \.                       '.'
--------------------------------------------------------------------------------
  )                        end of grouping
--------------------------------------------------------------------------------
  (                        group and capture to \1:
--------------------------------------------------------------------------------
    [^.\/]+                  any character except: '.', '\/' (1 or
                             more times (matching the most amount
                             possible))
--------------------------------------------------------------------------------
  )                        end of \1

JavaScript代码：

const url = "https://abcnews.go.com/"
const regex = /(?:https?:\/\/(?:www\.)?|www\.)([^.\/]+)/
const match = url.match(regex)
if (match) {
  console.log(match[1])
}

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