为什么我不能打印多个字符串？

helllo 发表于 Dev

你好

我可以打印一个字符串。但是，当我尝试添加两个字符串时，它仅显示第一个字符串吗？curr是链接列表的开始。如果我添加一个国家/地区并告诉程序进行打印，它将打印该国家/地区的信息。但是，如果我添加两个国家，它将仅打印第一个国家。

 void LinkedList::printList()
 {
    curr = head;
    while (curr)
    {
        cout << "Country Name: " << curr->name << ", " << "Gold: "  << curr->
        gold << ", " << "Silver: " << curr->silver << ", " << "Bronze: " << curr->bronze << "\n";
        curr = curr->next;
    }
}

bool LinkedList::addCountry(string newName, int gold, int silver, int bronze) {
    if (head == NULL)// Adding first element
    {
        head = new struct Country;
        if (head == NULL) return false; // could not create head linked list country
        head->name = newName;
        head->gold = gold;
        head->silver = silver;
        head->bronze = bronze;
        head->next = NULL;
        return true;
    } else {
        curr = head;
        while (curr) {
            curr = curr->next;
        }
        curr = new struct Country;
        if (curr == NULL)
            return false;
        curr->name = newName;
        curr->gold = gold;
        curr->silver = silver;
        curr->bronze = bronze;
        curr->next = NULL;
        return true;
    }
}

巴马克·谢米拉尼（Barmak Shemirani）

printList是正确的。但是在addCountry最后一个元素中必须指向刚刚插入的新元素。例如：

bool LinkedList::addCountry(string newName, int gold, int silver, int bronze) 
{
    Country *newNode = new Country;
    newNode->name = newName;
    newNode->gold = gold;
    newNode->silver = silver;
    newNode->bronze = bronze;
    newNode->next = NULL;

    if (head == NULL)
    {
        //adding first element:
        head = newNode;
    }
    else 
    {
        //find the last element currently in the list:
        Country *last = head;
        while (last->next)//<= ***** edited
            last = last->next;

        //set newNode as the new last element:
        last->next = newNode;
    }
    return true;
}