我需要构建Arrays一个Grouped UITableView，在每个表单元格中都有一个Title和Detail行。我从服务器获取了json输出，并将其设置为正确的形状以迭代这些UITableViewDataSource方法。但是将这些转换为这些UITableView函数可以引用的可读数组的最简单方法是什么？
标题数组用于组标题，因此它只是一维数组。我可以迭代。标题和详细信息数组都是二维的。我不知道如何在Swift中做到这一点。
"headings":["Tuesday, August 16, 2016","Wednesday, August 17, 2016","Thursday, August 18, 2016","Friday, August 19, 2016","Saturday, August 20, 2016","Sunday, August 21, 2016","Monday, August 22, 2016","Tuesday, August 23, 2016","Wednesday, August 24, 2016","Thursday, August 25, 2016","Friday, August 26, 2016","Saturday, August 27, 2016","Sunday, August 28, 2016","Monday, August 29, 2016","Tuesday, August 30, 2016","Wednesday, August 31, 2016","Thursday, September 1, 2016","Friday, September 2, 2016","Saturday, September 3, 2016","Sunday, September 4, 2016","Monday, September 5, 2016","Tuesday, September 6, 2016","Wednesday, September 7, 2016","Thursday, September 8, 2016","Friday, September 9, 2016","Saturday, September 10, 2016","Sunday, September 11, 2016","Monday, September 12, 2016","Tuesday, September 13, 2016","Wednesday, September 14, 2016","Thursday, September 15, 2016","Friday, September 16, 2016"],
"titles":[["Joe Johnson"],["Joe Johnson"],["Sandy Primmell","Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Sandy Primmell","Joe Johnson"],["Joe Johnson","Joe Johnson"],["Sandy Primmell","Joe Johnson"],["Mark Greene","Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Sandy Primmell","Joe Johnson"],["Joe Johnson"],["Sandy Primmell","Joe Johnson"],["Mark Greene","Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"]],
"details":[["OFF"],["OFF"],["Gregory","OFF"],["Gregory"],["OFF"],["OFF"],["OFF"],["Weekday Rounders","OFF"],["Weekday Rounders","Night Owls"],["Gregory","OFF"],["Gregory","OFF"],["OFF"],["OFF"],["OFF"],["Gregory"],["Gregory","OFF"],["Gregory"],["Gregory","OFF"],["Gregory","OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"]]
更新
这是我的Alamofire异步功能，可获取数据：
manager.request(.POST, getRouter(), parameters:["dev": 1, "app_action": "schedule", "type":getScheduleType(), "days_off":getScheduleDaysOff(), "period":getSchedulePeriod(), "begin_date":getScheduleBeginDate(), "end_date":getScheduleEndDate()])
.responseString {response in
print(response)
var json = JSON(response.result.value!);
// what I'm missing
}
另外，您可以使用诸如Argo或SwiftyJSON之类的JSON解析库，其创建目的是简化JSON解析。它们都经过了良好的测试，可以为您处理极端情况，例如JSON响应中缺少参数等。
假设JSON响应具有这种格式（来自Twitter API）
{
"users": [
{
"id": 2960784075,
"id_str": "2960784075",
...
}
}
请注意，Response该类包含一个数组，User该数组是另一个未在此处显示的类，但是您已经明白了。
struct Response: Decodable {
let users: [User]
let next_cursor_str: String
static func decode(j: JSON) -> Decoded<Response> {
return curry(Response.init)
<^> j <|| "users"
<*> j <| "next_cursor_str"
}
}
//Convert json String to foundation object
let json: AnyObject? = try? NSJSONSerialization.JSONObjectWithData(data, options: [])
//Check for nil
if let j: AnyObject = json {
//Map the foundation object to Response object
let response: Response? = decode(j)
}
如官方文档中所述：
if let dataFromString = jsonString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false) {
let json = JSON(data: dataFromString)
}
如果数据是数组，则使用索引
//Getting a double from a JSON Array
let name = json[0].double
如果数据是字典，则使用密钥
//Getting a string from a JSON Dictionary
let name = json["name"].stringValue
大批
//If json is .Array
//The `index` is 0..<json.count's string value
for (index,subJson):(String, JSON) in json {
//Do something you want
}
字典
//If json is .Dictionary
for (key,subJson):(String, JSON) in json {
//Do something you want
}
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