计算两个时间戳对象之间的时差-Java

Karthi Krazz 发表于 Dev

卡尔提·克拉兹（Karthi Krazz）

我有java.sql.date和java.sql.time对象，我需要找到日期之间的持续时间。

所以我通过使用上述日期和时间对象创建java.sql.timestamp对象

  Timestamp timestamp1 = new Timestamp(StartDate.getYear(),
        StartDate.getMonth(), StartDate.getDay(),
        StartTime.getHours(), StartTime.getMinutes(), 00,
        00);

这是mycode

String date = "2010-01-05";
    SimpleDateFormat sdf1 = new SimpleDateFormat("yyyy-MM-dd");
    java.util.Date date3 = null;
    try {
        date3 = sdf1.parse(date);
    } catch (ParseException e) {
        e.printStackTrace();
    }
    Date StartDate = new Date(date3.getTime());
    System.out.println("Date " + StartDate);

    String date2 = "2010-01-06";
    java.util.Date date4 = null;
    try {
        date4 = sdf1.parse(date2);
    } catch (ParseException exception) {
        exception.printStackTrace();
    }
    Date EndDate = new Date(date4.getTime());
    System.out.println("Date " + EndDate);

    String time = "01:00";
    DateFormat formatter = new SimpleDateFormat("HH:mm");
    java.sql.Time StartTime = null;
    try {
        StartTime = new java.sql.Time(formatter.parse(time).getTime());
    } catch (ParseException exception2) {
        exception2.printStackTrace();
    }
    System.out.println("TIMEEEEEEEEEE====" + StartTime);

    String time2 = "02:00";
    java.sql.Time EndTime = null;
    try {
        EndTime = new java.sql.Time(formatter.parse(time2).getTime());
    } catch (ParseException exception3) {
        exception3.printStackTrace();
    }
    System.out.println("TIMEEEEEEEEEE====" + EndTime);


    Timestamp timestamp1 = new Timestamp(StartDate.getYear(),
            StartDate.getMonth(), StartDate.getDay(),
            StartTime.getHours(), StartTime.getMinutes(), 00,
            00);
    Timestamp timestamp2 = new Timestamp(EndDate.getYear(),
            EndDate.getMonth(), EndDate.getDay(),
            EndTime.getHours(), EndTime.getMinutes(), 00, 00);

    long milliseconds = timestamp2.getTime() - timestamp1.getTime();
    int seconds = (int) milliseconds / 1000;

    // calculate hours minutes and seconds
    int hours = seconds / 3600;
    int minutes = (seconds % 3600) / 60;
    seconds = (seconds % 3600) % 60;
    System.out.println(hours+"h:"+minutes+"m:"+"00s");

测试用例

当我给出日期为2010-01-05和date2为2010-01-06时，我得到的输出如下

Date 2010-01-05
Date 2010-01-06
TIMEEEEEEEEEE====01:00:00
TIMEEEEEEEEEE====02:00:00
25h:0m:00s

当我给出日期为2010-01-05和date2为2010-01-11时，我得到如下所示的负值输出

Date 2010-01-05
Date 2010-01-11
TIMEEEEEEEEEE====01:00:00
TIMEEEEEEEEEE====02:00:00
-23h:0m:00s

如果我做错了什么，请帮助我纠正。提前致谢。

杜蒂

手动时间计算：-

转换日期（毫秒），并使用以下规则计算两个日期之间的差：

1000毫秒= 1秒
60秒= 1分钟
60分钟= 1小时
24小时= 1天

范例范例：-

package com.dps2.practice.dyuti;

import java.text.SimpleDateFormat;
import java.util.Date;

public class DateDifferentExample {

    public static void main(String[] args) {

        String dateStart = "08/11/2016 09:29:58";
        String dateStop = "08/12/2016 10:31:48";

        //HH converts hour in 24 hours format (0-23), day calculation
        SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");

        Date d1 = null;
        Date d2 = null;

        try {
            d1 = format.parse(dateStart);
            d2 = format.parse(dateStop);

            //in milliseconds
            long diff = d2.getTime() - d1.getTime();

            long diffSeconds = diff / 1000 % 60;
            long diffMinutes = diff / (60 * 1000) % 60;
            long diffHours = diff / (60 * 60 * 1000) % 24;
            long diffDays = diff / (24 * 60 * 60 * 1000);

            System.out.print(diffDays + " days, ");
            System.out.print(diffHours + " hours, ");
            System.out.print(diffMinutes + " minutes, ");
            System.out.print(diffSeconds + " seconds.");

        } catch (Exception e) {
            e.printStackTrace();
        }

    }

}