我有2张桌子,我正在尝试提取特定于材料的记录。所以我的查询如下
单日查询
SELECT tm.internal_name AS model_number, tm.item_description, tm.mrp, tm.asin, COUNT( product_serial_no ) AS `S_FTD`
FROM register_product_claim
INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
WHERE retailer_code = '9017'
AND register_product_claim.dt = '2016-08-04'
GROUP BY tm.asin
ORDER BY register_product_claim.dt DESC
LIMIT 0 , 30
明智的月
SELECT tm.internal_name AS model_number, tm.item_description, tm.mrp, tm.asin, COUNT( product_serial_no ) AS `S_MTD`
FROM register_product_claim
INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
WHERE retailer_code = '9017'
AND MONTH( register_product_claim.dt ) = '08'
GROUP BY tm.asin
ORDER BY register_product_claim.dt DESC
LIMIT 0 , 30
Qtr Wise
SELECT tm.internal_name AS model_number, tm.item_description, tm.mrp, tm.asin, COUNT( product_serial_no ) AS `S_QTD`
FROM register_product_claim
INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
WHERE retailer_code = '9017'
AND (
MONTH( register_product_claim.dt ) = '08'
OR MONTH( register_product_claim.dt ) = '07'
OR MONTH( register_product_claim.dt ) = '06'
)
GROUP BY tm.asin
ORDER BY register_product_claim.dt DESC
LIMIT 0 , 30
这一切都很好。
现在,我正在尝试合并所有查询。但是我无法合并它们。联盟,加入,但没有运气。
最后一个尝试是
SELECT *
FROM
(SELECT
tm.internal_name AS model_number, tm.item_description, tm.mrp, tm.asin,
COUNT(product_serial_no) as S_FTD
FROM
register_product_claim
INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
WHERE
retailer_code = '9017'
AND register_product_claim.dt = '2016-08-04'
GROUP BY tm.asin) as s1
Inner Join
(SELECT
COUNT(product_serial_no) as S_MTD
FROM
register_product_claim
INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
WHERE
retailer_code = '9017'
AND MONTH(register_product_claim.dt) = '08'
GROUP BY tm.asin) as s2
Inner Join
(SELECT
COUNT(product_serial_no) as S_QTD
FROM
register_product_claim
INNER JOIN tbl_model tm ON register_product_claim.model_number = tm.asin
WHERE
retailer_code = '9017'
AND (MONTH(register_product_claim.dt) = '08'
OR MONTH(register_product_claim.dt) = '07'
OR MONTH(register_product_claim.dt) = '06')
GROUP BY tm.asin) as s3
我的预期输出是
model_number | item_description | mrp | asin | S_FTD | S_MTD | S_QTD
S_FTD是一天,S_MTD是每月,S_QTD是每季度结果。
您可以使用条件聚合来做到这一点,将其调整为您的代码:
SELECT t.model_number,t.item_description,t.mrp,t.asin,
MAX(CASE WHEN t.new_col = 'D' then t.S_TD END) as S_FTD,
MAX(CASE WHEN t.new_col = 'M' then t.S_TD END) as S_MTD,
MAX(CASE WHEN t.new_col = 'Q' then t.S_TD END) as S_QTD
FROM (
SELECT ss.*,'D' as new_col FROM (Daily Query) ss
UNION ALL
SELECT ss1.*,'M' FROM (Monthly Query) ss1
UNION ALL
SELECT ss2.*,'Q' FROM (Quarter Query) ss2
) t
GROUP BY t.model_number,t.item_description,t.mrp,t.asin
注意:您必须S_FTD
在日常查询中S_TD
为该列添加别名,才能正常工作。
本文收集自互联网,转载请注明来源。
如有侵权,请联系[email protected] 删除。
我来说两句