如何在jQuery中将段落分为句子

Ahmad 发表于 Dev

艾哈迈德

我想将一个段落分成jquery中的句子。可以说我有一段

This is a wordpress plugin. its older version was 2.3.4 and new version is 2.4. But the version 2.4 had a lot of bungs. Can we solve it?

我想把它分解成

This is a wordpress plugin.
its older version was 2.3.4 and new version is 2.4.
But the version 2.4 had a lot of bungs.
Can we solve it?

有什么解决方案吗？我试图使用此功能，但当数字到来时它也将句子分开。

var result = str.match( /[^\.!\?]+[\.!\?]+/g );

谢谢

埃米尔·S·约根森

您可以使用类似的方法/((\.|\?|\!)\s)|(\?|\!)|(\.$)/g来获取元素。这是每个捕获组的伪分解：

((\.|\?|\!)\s)：任意.，?或!后跟空白。
(\?|\!)：任何独立的?或!。
(\.$)：任何.后跟end-of-line。（根据字符串，这一点可能是不必要的）

这是使您步入正轨的粗略代码：

console.clear();
var str = 'This is a wordpress plugin. its older version was 2.3.4 and new version is 2.4. But the version 2.4 had a lot of bungs. Can we solve it?';
console.log('"' + str + '"');
console.log('Becomes:');
console.log('"' + str.replace(/((\.|\?|\!)\s)|(\?|\!)|(\.$)/g, ".\n") + '"');

为了解决不同的符号，“真实交易”将必须适当地替换几轮才能解决：

console.clear();
var str = 'This is a wordpress plugin. its older version was 2.3.4 and new version is 2.4. But the version 2.4 had a lot of bungs. Can we solve it?';
str = str
  //"all"
  //.replace(/((\.|\?|\!)\s)|(\?|\!)|(\.$)/g,".\n")
  //"."
  .replace(/((\.)\s)|(\.$)/g, ".\n")
  //"?"
  .replace(/((\?)\s)|(\?)/g, "?\n")
  //"!"
  .replace(/((\!)\s)|(\!)/g, "!\n")
console.log(str)

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