从数组中求和

用户名

我有2个数组,如下所示。

我需要获取与之相关的每个里程碑的进度总和。

因此,在任务数组中,我可以看到1578453e53090b(线框里程碑)的进度总和为15。

理想的结果是将进度总计附加到每个里程碑上。希望这是有道理的。

$milestones = 
Array
(
[0] => Array
    (
        [id] => 1578453e53090b
        [milestone] => Wireframe
        [assigned_to] => 9
    )

[1] => Array
    (
        [id] => 1578453e530975
        [milestone] => Development
    )

[2] => Array
    (
        [id] => 1578453e530943
        [milestone] => Design
        [assigned_to] => 2
    )

)


$tasks =
Array
(
[0] => Array
    (
        [id] => 15786dc59333f2
        [status] => Open
        [progress] => 5
        [milestone] => 1578453e53090b
    )

[1] => Array
    (
        [id] => 15786dc669d451
        [status] => Open
        [progress] => 10
        [milestone] => 1578453e53090b
    )

[2] => Array
    (
        [id] => 15786dc7ccbea3
        [status] => Open
        [progress] => 20
        [milestone] => 1578453e530943
    )
)
凯文

做到这一点的方法之一就是使用foreach使用第一个foreachmilestones获取将匹配第二中IDforeachtasksmilestone

之后,请使用一个$total可连续使用的简单容器,并使用simple对其进行匹配if

foreach($milestones as &$m) {
                //     ^ add reference to make changes
    $total = 0; // initialize total holder
    foreach($tasks as $task) {
        if($task['milestone'] === $m['id']) { // if it matches
            $total += $task['progress']; // add
        }
    }

    $m['total'] = $total; // after its done, add another key pair being total and its value
}

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