使用Firebase适配器填充ListView

APP Bird 发表于 Dev

APP鸟

我尝试使用Firebase UI使用Firebase适配器填充列表视图时收到这些错误

com.google.firebase.database.DatabaseException：无法将类型java.util.HashMap的值转换为String com.google.firebase.database.DatabaseException：类java.util.HashMap具有通用类型参数，请改用GenericTypeIndicator

这是代码

     DatabaseReference ref = FirebaseDatabase.getInstance().getReference();
     DatabaseReference a = ref.child("info");

        final FirebaseListAdapter<String> adapter =
              new FirebaseListAdapter<String>(this,String.class,android.R.layout.simple_list_item_1,a) {
                  @Override
                  protected void populateView(View v, String model, int position) {

                      TextView text = (TextView) findViewById(android.R.id.text1);
                      text.setText(model);

                  }

这是json数据的示例

 "info" : {
   "KSTUJILdwPN305Fs7ujhga4knlG3" : {
     "File Info" : {
       "-JFRkA855rfOU7GtcK4" : {
         "Name" : "John",
         "Adress" : "Test Adress",
         "Favourite_food" : "Bread",
       },

乌古尔

info节点未引用您的数据模型。它可能包含子节点。因此，要获取模型，您应该使用像这样的参考。

 DatabaseReference a = ref.child("info").child(info_id).child("File Info").child(file_id);

并且您应该具有FileInfo模型而不是String模型以用于

populateView(View v, FileInfo model, int position):

和模型

public class FileInfo {

private String Name;
private String Adress;
private String Favourite_food;

public FileInfo() {
}

public FileInfo(String Name, String Adress, String Favourite_food) {
    this.Name = Name;
    this.Adress = Adress;
    this.Favourite_food = Favourite_food;
}

public String getName() {
    return Name;
}

public void setName(String Name) {
    this.Name = Name;
}

public String getAdress() {
    return Adress;
}

public void setAdress(String Adress) {
    this.Adress = Adress;
}

public String getFavourite_food() {
    return Favourite_food;
}

public void setFavourite_food(String Favourite_food) {
    this.Favourite_food = Favourite_food;
}

}