我可以在ODB中将const对象传递给db.persist吗？

我正在尝试ODB ORM，并且必须坚持使用接口，因此我需要获取一个const对象并将其持久化。我不确定ODB API是否允许持久保留const对象，因为某些部分似乎已经为此准备好了，但是它不起作用。

我在这里从gcc收到此错误：

void OdbReportRW::write_object(const MyObject &my_object)
{
    odb::core::transaction t{db->begin()};
    db->persist(my_object);
    t.commit();
}

这是错误，我认为它说my_object不应为const：

In file included from /usr/local/include/odb/database.hxx:632:0,
from odb_report.hpp:21,
from src/vcf/odb_report.cpp:18:
/usr/local/include/odb/database.txx: In instantiation of ‘typename odb::object_traits<T>::id_type odb::database::persist_(T&) [with T = const MyObject; odb::database_id DB = (odb::database_id)5u; typename odb::object_traits<T>::id_type = long unsigned int]’:
/usr/local/include/odb/database.ixx:167:45:   required from ‘typename odb::object_traits<T>::id_type odb::database::persist(const T&) [with T = MyObject; typename odb::object_traits<T>::id_type = long unsigned int]’
src/vcf/odb_report.cpp:134:26:   required from here
/usr/local/include/odb/database.txx:38:39: error: no matching function for call to ‘odb::object_traits_impl<MyObject, (odb::database_id)5u>::persist(odb::database&, const MyObject&)’
object_traits::persist (*this, obj);
^
/usr/local/include/odb/database.txx:38:39: note: candidate is:
In file included from src/vcf/odb_report.cpp:27:0:
my-object-error-odb.hxx:247:5: note: static void odb::access::object_traits_impl<MyObject, (odb::database_id)1u>::persist(odb::database&, odb::access::object_traits<MyObject>::object_type&)
persist (database&, object_type&);
^
my-object-odb.hxx:247:5: note:   no known conversion for argument 2 from ‘const MyObject’ to ‘odb::access::object_traits<MyObject>::object_type& {aka MyObject&}’

与c相同的错误，更具描述性：

In file included from src/vcf/odb_report.cpp:18:
In file included from inc/vcf/odb_report.hpp:21:
In file included from /usr/local/include/odb/database.hxx:632:
/usr/local/include/odb/database.txx:38:36: error: binding of reference to type 'object_type' (aka 'MyObject') to a value of type 'const MyObject' drops qualifiers
    object_traits::persist (*this, obj);
                                   ^~~
/usr/local/include/odb/database.ixx:167:12: note: in instantiation of function template specialization 'odb::database::persist_<const MyObject, 5>' requested here
    return persist_<const T, id_common> (obj);
           ^
src/vcf/odb_report.cpp:134:13: note: in instantiation of function template specialization 'odb::database::persist<MyObject>' requested here
        db->persist(my_object);
            ^
inc/vcf/error-odb.hxx:247:37: note: passing argument to parameter here
    persist (database&, object_type&);
                                    ^

但是，我可以在数据库界面（从odb中）看到，提供了两种持久性类型：引用和const引用（以及其他带指针的）：

// in odb/database.hxx
template <typename T>
typename object_traits<T>::id_type
persist (T& object);

template <typename T>
typename object_traits<T>::id_type
persist (const T& object);

当类中没有要持久化的默认构造函数（此处为MyObject）时find，我看到了类似的错误（对于，不是persist），但是它在那里，所以这不是问题。我已经检查过默认构造函数仅find在生成的代码中生成一个额外的方法。

它可以删除我的write_object方法中的const说明符，但正如我所说，我必须坚持使用接口。

有什么想法可以保留const对象吗？