给定一个Map<String, Object>
,其中值是aString
或另一个Map<String, Object>
,那么如何使用Java 8将地图展平到单个值列表?
例子:
Map - "key1" -> "value1"
- "key2" -> "value2"
- "key3" -> Map - "key3.1" -> "value3.1"
- "key3.2" -> "value3.2"
- "key3.3" -> Map - "key3.3.1" -> "value3.3.1"
- "key3.3.2" -> "value3.3.2"
对于上面的示例,我想要以下列表:
value1
value2
value3.1
value3.2
value3.3.1
value3.3.2
我知道可以这样做:
public static void main(String args[]) throws Exception {
//Map with nested maps with nested maps with nested maps with nested......
Map<String, Object> map = getSomeMapWithNestedMaps();
List<Object> values = new ArrayList<>();
addToList(map, values);
for (Object o:values) {
System.out.println(o);
}
}
static void addToList(Map<String, Object>map, List<Object> list) {
for (Object o:map.values()) {
if (o instanceof Map) {
addToList((Map<String, Object>)o, list);
} else {
list.add(o);
}
}
}
我该如何使用Stream
?
编辑:
经过一番游戏后,我发现了:
public static void main(String args[]) throws Exception {
//Map with nested maps with nested maps with nested maps with nested......
Map<String, Object> map = getSomeMapWithNestedMaps();
//Recursively flatten maps and print out all values
List<Object> list= flatten(map.values().stream()).collect(Collectors.toList());
}
static Stream<Object> flatten(Stream<Object> stream) {
return stream.flatMap((o) ->
(o instanceof Map) ? flatten(((Map<String, Object>)o).values().stream()) : Stream.of(o)
);
}
您可以定义一个递归方法来展平一个地图并将其用作函数Stream#flatMap
或直接调用它来使用它。
例子:
public class FlatMap {
public static Stream<Object> flatten(Object o) {
if (o instanceof Map<?, ?>) {
return ((Map<?, ?>) o).values().stream().flatMap(FlatMap::flatten);
}
return Stream.of(o);
}
public static void main(String[] args) {
Map<String, Object> map0 = new TreeMap<>();
map0.put("key1", "value1");
map0.put("key2", "value2");
Map<String, Object> map1 = new TreeMap<>();
map0.put("key3", map1);
map1.put("key3.1", "value3.1");
map1.put("key3.2", "value3.2");
Map<String, Object> map2 = new TreeMap<>();
map1.put("key3.3", map2);
map2.put("key3.3.1", "value3.3.1");
map2.put("key3.3.2", "value3.3.2");
List<Object> collect = map0.values().stream()
.flatMap(FlatMap::flatten)
.collect(Collectors.toList());
// or
List<Object> collect2 = flatten(map0).collect(Collectors.toList());
System.out.println(collect);
}
}
对于给定的嵌套地图,它会打印
[value1,value2,value3.1,value3.2,value3.3.1,value3.3.2]
本文收集自互联网,转载请注明来源。
如有侵权,请联系[email protected] 删除。
我来说两句