如何在ASP.NET Web API异步控制器方法中返回对象列表或将列表包装在Task对象中?
班级:
public class SubscriberHistory
{
public string Date;
public string Message;
public SubscriberHistory(string Date, string Message)
{
this.Date = Date;
this.Message = Message;
}
}
控制器:
[HttpGet("[action]/{accountNumber}")]
public Task<SubscriberHistory> GetSubscriberHistory(string accountNumber)
{
SubscriberManager subsManager = new SubscriberManager();
return subsManager.GetSubscriberHistoryByAccountNumber(accountNumber);
}
控制器管理员:
public async List<SubscriberHistory> GetSubscriberHistory()
{
List<SubscriberHistory> List = new List<SubscriberHistory>();
// HttpClient get data
return List; // ?
}
Task
如果您不执行任何操作,请不要从操作方法中返回a async
:它是无用的,并且还会给您的调用增加不必要的开销。
要返回对象列表,只需声明正确的返回类型:
[HttpGet("[action]/{accountNumber}")]
public List<SubscriberHistory> GetSubscriberHistory(string accountNumber)
{
SubscriberManager subsManager = new SubscriberManager();
return subsManager.GetSubscriberHistoryByAccountNumber(accountNumber);
}
相反,如果要异步执行操作,则必须返回aTask<T>
并等待结果:
[HttpGet("[action]/{accountNumber}")]
public async Task<List<SubscriberHistory>> GetSubscriberHistory(string accountNumber)
{
SubscriberManager subsManager = new SubscriberManager();
return await subsManager.GetSubscriberHistoryByAccountNumber(accountNumber);
}
在您的经理中:
public async Task<List<SubscriberHistory>> GetSubscriberHistory()
{
List<SubscriberHistory> list = new List<SubscriberHistory>();
var result = await client.GetAsync("http://myhost/mypath");
//Your code here
return list;
}
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