等待一个进程完成并执行另一个进程

我想在进程之间进行同步，我的计算机有2个核心，用户可以从命令行输入仿真编号，如果输入大于2，则第3个和其余进程必须等到其中一个进程完成为止。如果其中一个完成，则应该执行下一个进程，例如，前两个进程已经在进行中，可以说，第一个已经在第二个进程之前完成了，现在应该执行第三个进程。可以看到没有找到anywait命令，该怎么办？这是我的脚本：

#!/bin/bash
# My first script

count=2
echo -n "Please enter the number of simulation :"
read number
echo "Please enter the algorithm type  "
printf "0 for NNA\n1 for SPA\n2 for EEEA :"

while read type; do
    case $type in
        0 ) cd /home/cea/Desktop/simulation/wsnfuture 
        taskset -c 0 ./wsnfuture -u Cmdenv omnetpp.ini > /home/cea/Desktop/simulation/RESULTS/NNA/NNA0/0 &
        taskset -c 1 ./wsnfuture -u Cmdenv omnetpp.ini > /home/cea/Desktop/simulation/RESULTS/NNA/NNA0/1 &
        while [ $count -lt $number ]; do
        anywait
            cd /home/cea/Desktop/simulation/wsnfuture 
        mkdir /home/cea/Desktop/simulation/RESULTS/NNA/NNA$count
        taskset -c $((count % 2)) ./wsnfuture -u Cmdenv omnetpp.ini > /home/cea/Desktop/simulation/RESULTS/NNA/NNA$count/$count &
            count=$((count + 1))
        done 
        ;;
        1 ) while [ $count -lt $number ]; do
            cd /home/cea/Desktop/simulation/wsnfuture1
        taskset -c $((count % 2)) ./wsnfuture -u Cmdenv omnetpp.ini > /home/cea/Desktop/simulation/RESULTS/SPA/$count &
            count=$((count + 1))
        done 
        ;;
        2 ) while [ $count -lt $number ]; do
            cd /home/cea/Desktop/simulation/wsnfuture2
        taskset -c $((count % 2)) ./wsnfuture -u Cmdenv omnetpp.ini > /home/cea/Desktop/simulation/RESULTS/EEEA/$count &
            count=$((count + 1))
        done 
        ;;
        * ) echo "You did not enter a number"
        echo "between 0 and 2."
        echo "Please enter the algorithm type  "
        printf "0 for NNA\n1 for SPA\n2 for EEEA :"

    esac

done

function anywait(){
 while ps axg | grep -v grep | grep wsnfuture> /dev/null; do sleep 1; done
}