我在做一些家庭作业时很忙，但我坚持做这项运动。任务是在3列中创建12个标签，并在每列下方创建一个单选按钮。选择单选按钮时，其上方行的颜色需要更改。当未选中单选按钮时，它们将变回原来的颜色。程序启动时，不必选择任何单选按钮。
我有两个问题。
这是我的代码：
# Import the Tkinter functions
from Tkinter import *
# Create a window
the_window = Tk()
the_window.geometry('460x200')
# Give the window a title
the_window.title('Show Columns')
#Change first set colour
def change_first_set_colour():
label1.configure(bg="blue")
label2.configure(bg="blue")
label3.configure(bg="blue")
label4.configure(bg="blue")
#Change first set colour
def change_second_set_colour():
label5.configure(bg="blue")
label6.configure(bg="blue")
label7.configure(bg="blue")
label8.configure(bg="blue")
#Change first set colour
def change_third_set_colour():
label9.configure(bg="blue")
label10.configure(bg="blue")
label11.configure(bg="blue")
label12.configure(bg="blue")
#Create label1
label1 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label1.place(x=5, y=5)
#Create label2
label2 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label2.place(x=5, y=45)
#Create label3
label3 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label3.place(x=5, y=85)
#Create label4
label4 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label4.place(x=5, y=125)
#Create Radio Button 1
Radio_1 = Radiobutton(the_window,
text="First",
command=change_first_set_colour(),
value=1).place(x=50, y=165)
#Create label5
label5 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label5.place(x=155, y=5)
#Create label6
label6 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label6.place(x=155, y=45)
#Create label7
label7 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label7.place(x=155, y=85)
#Create label8
label8 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label8.place(x=155, y=125)
#Create Radio Button 2
Radio_2 = Radiobutton(the_window,
text="Second",
command=change_second_set_colour(),
value=2).place(x=180, y=165)
#Create label9
label9 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label9.place(x=305, y=5)
#Create label10
label10 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label10.place(x=305, y=45)
#Create label11
label11 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label11.place(x=305, y=85)
#Create label12
label12 = Label(the_window, bg="grey", fg="black", width=20, height=2)
label12.place(x=305, y=125)
Radio_3 = Radiobutton(the_window,
text="Third",
command=change_third_set_colour(),
value=3).place(x=345, y=165)
#----------------------------------------------------------------
# Start the event loop to react to user inputs
the_window.mainloop()
PS：我的大学仍然使用Python 2.7
我无法弄清楚如何在未选中所有单选按钮的情况下启动程序。当前，一次选择两个。
使用变量值与单选按钮的任何值都不匹配的变量（例如0）。
程序加载时，更改框颜色的功能似乎正在运行。它们不会变回原始颜色。
传递函数本身，而不返回函数调用的值。换句话说，删除()
command=change_third_set_colour() -> command=change_third_set_colour
BTW，place应分别叫，否则Radio_1，Radio_2，Radio_3成为None因place方法返回None。
radio_var = IntVar(value=0)
Radio_1 = Radiobutton(the_window,
text="First",
variable=radio_var, # <---
command=change_first_set_colour, # <---
value=1)
Radio_1.place(x=50, y=165) # <---
...
Radio_2 = Radiobutton(the_window,
text="Second",
variable=radio_var, # <---
command=change_second_set_colour, # <---
value=2)
Radio_2.place(x=180, y=165) # <---
...
Radio_3 = Radiobutton(the_window,
text="Third",
variable=radio_var, # <---
command=change_third_set_colour, # <---
value=3)
Radio_3.place(x=345, y=165) # <---
change_first_set_colour，change_second_set_colour，change_third_set_colour应修改重置其他标签的颜色。
本文收集自互联网，转载请注明来源。
如有侵权，请联系[email protected] 删除。
我来说两句