我不是Java程序员,但是需要编写Java程序来解析较大的(400mb)xml文件。我选择了vtd-xml,但不知道如何正确引用该软件包。我不想使用maven / gradle,因为我不经常使用Java进行编程,而实际上只需要引用该软件包即可。我有:
import com.ximpleware.*;
在我的Java文件的顶部。我将vtd-xml源代码保存在与Java文件相同的目录中,因此目录结构如下所示:
my_java.java
vtd_xml/com
vtd_xml/example
vtd_xml/install.txt
vtd_xml/Readme.txt
vtd_xml/ximpleware_2.12-java-light.zip
vtd_xml/vtd-xml_light-2-12.jar
我导出了类路径,以便
echo $CLASSPATH
退货
vtd_xml/vtd-xml_light-2-12.jar
但是当我去编译我的java文件时,
javac my_java.java
我收到以下(令人沮丧的)错误:
zephyr_4.java:18: error: cannot find symbol
XMLModifier xm = new XMLModifier(vn);
^
symbol: class XMLModifier
location: class zephyr_4
zephyr_4.java:18: error: cannot find symbol
XMLModifier xm = new XMLModifier(vn);
^
symbol: class XMLModifier
location: class zephyr_4
zephyr_4.java:23: error: cannot find symbol
ap.selectXPath(query);
^
symbol: method selectXPath(String)
location: variable ap of type AutoPilot
zephyr_4.java:28: error: cannot find symbol
while((i=ap.evalXPathToNumber())!=-1){
^
symbol: method evalXPathToNumber()
location: variable ap of type AutoPilot
zephyr_4.java:29: error: cannot find symbol
System.out.println(vn.toNormalizedPathString());
^
symbol: method toNormalizedPathString()
location: variable vn of type VTDNav
我究竟做错了什么?如果有帮助,这是我的源代码:
import java.io.*;
import com.ximpleware.*;
import java.util.*;
public class my_java {
public static void main(String argv[]) throws NavException, IOException{
// open a file and read the content into a byte array
VTDGen vg = new VTDGen();
if (vg.parseFile("pubmed_result.xml", true)){
VTDNav vn = vg.getNav();
AutoPilot ap = new AutoPilot(vn);
XMLModifier xm = new XMLModifier(vn);
String query = "count(//PubmedArticleSet/PubmedArticle"
+ "/MedlineCitation/Article"
+ "/AuthorList/Author[contains(LastName,\"Sangani\") and "
+ "contains(ForeName, \"Rahul G\")])";
ap.selectXPath(query);
ap.bind(vn);
int i = -1;
while((i=ap.evalXPathToNumber())!=-1){
System.out.println(vn.toNormalizedPathString());
}
}
}
}
更新我的符号错误仍然看起来像:
zephyr_4.java:8: error: cannot find symbol
import com.ximpleware.VTDGen;
^
symbol: class VTDGen
location: package com.ximpleware
zephyr_4.java:10: error: cannot find symbol
import com.ximpleware.AutoPilot;
^
symbol: class AutoPilot
location: package com.ximpleware
zephyr_4.java:11: error: cannot find symbol
import com.ximpleware.XMLModifier;
^
symbol: class XMLModifier
location: package com.ximpleware
zephyr_4.java:16: error: cannot find symbol
public static void main(String argv[]) throws NavException, IOException{
^
symbol: class NavException
location: class zephyr_4
zephyr_4.java:18: error: cannot find symbol
VTDGen vg = new VTDGen();
^
symbol: class VTDGen
location: class zephyr_4
zephyr_4.java:18: error: cannot find symbol
VTDGen vg = new VTDGen();
^
symbol: class VTDGen
location: class zephyr_4
zephyr_4.java:21: error: cannot find symbol
AutoPilot ap = new AutoPilot(vn);
^
symbol: class AutoPilot
location: class zephyr_4
zephyr_4.java:21: error: cannot find symbol
AutoPilot ap = new AutoPilot(vn);
^
symbol: class AutoPilot
location: class zephyr_4
zephyr_4.java:22: error: cannot find symbol
XMLModifier xm = new XMLModifier(vn);
^
symbol: class XMLModifier
location: class zephyr_4
zephyr_4.java:22: error: cannot find symbol
XMLModifier xm = new XMLModifier(vn);
^
symbol: class XMLModifier
location: class zephyr_4
10 errors
您需要返回到vtd-xml网站并下载vtd-xml的标准版...来解释这一点:
实际上有3个vtd-xml版本:
---轻量级的剥离了用于移动设备的准系统解析器---标准是功能最强大/功能最丰富和完整的一个---扩展版功能较少,但支持高达256 gb的文档
因此,您正在寻找的是标准版,我认为...
链接在这里...
您的代码中有一个小错误
ap.evalXPathToNumber返回一个双精度值,而不是节点集,因此您可以直接分配返回的结果并使用它。
另一个建议是,您可以打开VTDGen的vg.setLCLevel(5),这可能有助于提高xpath性能。
本文收集自互联网,转载请注明来源。
如有侵权,请联系[email protected] 删除。
我来说两句