我有一个javascript函数,它计算两个日期之间的工作日,它可以工作,但是问题是它不考虑假期。我如何修改此功能,例如通过在异常数组中添加假期?
在互联网上搜索了有关此问题的信息,但未找到有关假期例外的信息。
例如,假日数组:
var holidays = ['2016-05-03','2016-05-05'];
我有一个函数来计算这个:
function workingDaysBetweenDates(d0, d1) {
var startDate = parseDate(d0);
var endDate = parseDate(d1);
// Validate input
if (endDate < startDate)
return 0;
// Calculate days between dates
var millisecondsPerDay = 86400 * 1000; // Day in milliseconds
startDate.setHours(0,0,0,1); // Start just after midnight
endDate.setHours(23,59,59,999); // End just before midnight
var diff = endDate - startDate; // Milliseconds between datetime objects
var days = Math.ceil(diff / millisecondsPerDay);
// Subtract two weekend days for every week in between
var weeks = Math.floor(days / 7);
days = days - (weeks * 2);
// Handle special cases
var startDay = startDate.getDay();
var endDay = endDate.getDay();
// Remove weekend not previously removed.
if (startDay - endDay > 1)
days = days - 2;
// Remove start day if span starts on Sunday but ends before Saturday
if (startDay == 0 && endDay != 6)
days = days - 1
// Remove end day if span ends on Saturday but starts after Sunday
if (endDay == 6 && startDay != 0)
days = days - 1
return days;
}
function parseDate(input) {
// Transform date from text to date
var parts = input.match(/(\d+)/g);
// new Date(year, month [, date [, hours[, minutes[, seconds[, ms]]]]])
return new Date(parts[0], parts[1]-1, parts[2]); // months are 0-based
}
在jsfiddle中做了一个例子:
也许还有一些其他功能可以在Jquery中轻松使用?
最简单的方法是在开始日期和结束日期之间寻找这些天。
编辑:我添加了一个额外的验证,以确保仅从holidays
阵列中减去工作日。
$(document).ready(() => {
$('#calc').click(() => {
var d1 = $('#d1').val();
var d2 = $('#d2').val();
$('#dif').text(workingDaysBetweenDates(d1,d2));
});
});
let workingDaysBetweenDates = (d0, d1) => {
/* Two working days and an sunday (not working day) */
var holidays = ['2016-05-03', '2016-05-05', '2016-05-07'];
var startDate = parseDate(d0);
var endDate = parseDate(d1);
// Validate input
if (endDate <= startDate) {
return 0;
}
// Calculate days between dates
var millisecondsPerDay = 86400 * 1000; // Day in milliseconds
startDate.setHours(0, 0, 0, 1); // Start just after midnight
endDate.setHours(23, 59, 59, 999); // End just before midnight
var diff = endDate - startDate; // Milliseconds between datetime objects
var days = Math.ceil(diff / millisecondsPerDay);
// Subtract two weekend days for every week in between
var weeks = Math.floor(days / 7);
days -= weeks * 2;
// Handle special cases
var startDay = startDate.getDay();
var endDay = endDate.getDay();
// Remove weekend not previously removed.
if (startDay - endDay > 1) {
days -= 2;
}
// Remove start day if span starts on Sunday but ends before Saturday
if (startDay == 0 && endDay != 6) {
days--;
}
// Remove end day if span ends on Saturday but starts after Sunday
if (endDay == 6 && startDay != 0) {
days--;
}
/* Here is the code */
holidays.forEach(day => {
if ((day >= d0) && (day <= d1)) {
/* If it is not saturday (6) or sunday (0), substract it */
if ((parseDate(day).getDay() % 6) != 0) {
days--;
}
}
});
return days;
}
function parseDate(input) {
// Transform date from text to date
var parts = input.match(/(\d+)/g);
// new Date(year, month [, date [, hours[, minutes[, seconds[, ms]]]]])
return new Date(parts[0], parts[1]-1, parts[2]); // months are 0-based
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" id="d1" value="2016-05-02"><br>
<input type="text" id="d2" value="2016-05-08">
<p>Working days count: <span id="dif"></span></p>
<button id="calc">Calc</button>
<p>
Now it shows 5 days, but I need for example add holidays
3 and 5 May (2016-05-03 and 2016-05-05) so the result will be 3 working days
</p>
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