我正在创建一个简单的程序,该程序将获取姓名,年龄和喜欢的号码。问题是,当用户选择输入1个以上的收藏夹号码时,会出现此异常。
请帮助我解决在测试类-> favnum2方法中仍然使用椭圆的问题。*
测试班
import java.util.Scanner;
public class testing{
public static Scanner input;
public static void main(String[] args){
boolean choicerepeat=true;
int favnumoftimes;
while(choicerepeat==true){
input = new Scanner(System.in);
testing2 obj1 = new testing2();
String name="";
int age=0;
favnumoftimes=0;
double favnum=0, favnumarr[]=new double[999];
boolean choice1;
System.out.print("What is your name? ");
name = input.nextLine();
System.out.print("What is your age? ");
age = input.nextInt();
obj1.message1(name);
obj1.message2(age);
System.out.print(name+" do you only have one favorite number? (If yes type 'true' else 'false' - NOTE: lowercase only) ");
choice1 = input.nextBoolean();
if(choice1==true)
favnum1();
else{
System.out.println("How many favorite numbers do you have "+name+"? ");
favnumoftimes = input.nextInt();
for(int a=0;a<favnumoftimes;a++){
System.out.print("Enter favorite number "+ (a+1) +": ");
favnumarr[a]=input.nextDouble();
}
for(int a=0;a<favnumarr.length;a++){
favnum2(favnumoftimes, favnumarr[a]);
}
}
System.out.println();
System.out.println("Do you want to restart the program? (true(Yes) else false(No)) ");
choicerepeat = input.nextBoolean();
}
}
public static void favnum1(){
System.out.print("Enter favorite number: ");
double favnumholder1 = input.nextDouble();
System.out.println("Your favorite number is "+favnumholder1+" ." );
}
public static double favnum2(int favnumoftimesholder,double...favtemphold2){
System.out.print("Your favorite numbers are ");
for(int a=0;a<=favnumoftimesholder;a++){
System.out.print(favtemphold2[a]+", ");
}
return 0;
}
}
testing2类
public class testing2{
public static String message1(String nameholder){
for(int a=0;a<nameholder.length();a++){
char strholder = nameholder.charAt(a);
if(Character.isDigit(a)){
System.out.println("Names don't have numbers... ");
break;
}
else continue;
}
System.out.println("\nHi "+nameholder+"! Welcome to my simple program. ");
return nameholder;
}
public static int message2(int ageholder){
System.out.println("Your age is "+ageholder+" years old? Oh my goodness. ");
System.out.println();
return ageholder;
}
}
问题在于varargs创建新数组,其长度等于传递的参数数量。这样double...favtemphold2
将创建一个新数组,favtemphold2
并且由于您仅传递了1个元素(favnum2(favnumoftimes, favnumarr[a]);
),因此该数组的长度为1。
您可能想要传递更多的元素或整个数组,即favnum2(favnumoftimes, favnumarr);
。由于double...
基本上是语法糖,因为double[]
它们相等,因此为双vararg传递双精度数组将起作用。
但是,警告您将来要使用varargs:请谨慎使用,Object...
因为数组也是对象。
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