如何使用SQL Server在查询中按天将结果分组？

Esraa_92 发表于 Dev

Esraa_92

我的日记表具有以下表结构：

 CREATE TABLE Diary
(
     [IdDiary] bigint, 
     [UserId] int,
     [IdDay] numeric(18,0),
     [IsAnExtraHour] bit
);

INSERT INTO Diary ([IdDiary],  [UserId],  [IdDay], [IsAnExtraHour])
values 
(51, 1409, 1, 0),
(52, 1409, 1, 1),
(53, 1409, 3, 0),
(54, 1409, 5, 0),
(55, 1409, 5, 1),
(56, 1408, 2, 0);

而DiaryTimetable表的此结构为：

CREATE TABLE DiaryTimetable
(
     [IdDiary] bigint, 
     [Hour] varchar(50)
);

  INSERT INTO DiaryTimetable ([IdDiary], [Hour])
VALUES
    (51, '09:00'),
    (51, '09:30'),
    (51, '10:00'),
    (51, '10:30'),
    (51, '11:00'),
    (52, '15:00'),
    (52, '15:30'),
    (52, '16:00'),
    (52, '16:30'),
    (52, '17:00'),
    (53, '11:00'),
    (53, '11:30'),
    (53, '12:00'),
    (53, '12:30'),
    (53, '13:00'),
    (54, '10:00'),
    (54, '10:30'),
    (54, '11:00'),
    (54, '11:30'),
    (54, '12:00'),
    (55, '16:00'),
    (55, '16:30'),
    (55, '17:00'),
    (55, '17:30'),
    (55, '18:00'),
    (56, '15:00'),
    (56, '15:30'),
    (56, '16:00'),
    (56, '16:30'),
    (56, '17:00');

我使用此查询来获取用户ID 1409的最大小时数和最小小时数，以获取每天输入的时间和离开工作的时间。idday与星期几相对应。例如1是星期一，2是星期二，依此类推...

 SELECT d.IdDiary, d.IdDay, MIN(Hour) as 'Start Time', MAX(Hour) as 'End Time', IsAnExtraHour
FROM Diary AS d
LEFT JOIN DiaryTimetable AS dt ON d.IdDiary = dt.IdDiary
where userid = 1409
GROUP BY d.IdDiary, d.IdDay, IsAnExtraHour

此查询给出以下结果：

我想得到这个结果：

    Day       Start Time    End Time    Start Extra Time    End Extra Time
    -----     ----------    --------    ---------------     ---------------
   Monday       09:00         11:00        15:00                17:00
   Wednessday   11:00         13:00        
   Friday       10:00         12:00        16:00                18:00

我有一列（IsAnExtraHour），该列指示该行是否一天中有额外的时间，例如，受雇者在星期一的09:00至11:00开始工作，然后在下午的15:00至17再次工作： 00，所以我想知道如何将这些时间分组在同一行中，希望我已经能够表达清楚，我接受建议谢谢。

夸斯诺伊

SELECT  d.IdDay,
        MIN(CASE WHEN isAnExtraHour = 0 THEN hour END) as 'Start Time',
        MAX(CASE WHEN isAnExtraHour = 0 THEN hour END) as 'End Time',
        MIN(CASE WHEN isAnExtraHour = 1 THEN hour END) as 'Start Extra Time',
        MAX(CASE WHEN isAnExtraHour = 1 THEN hour END) as 'End Extra Time'
FROM    Diary AS d
LEFT JOIN
        DiaryTimetable AS dt
ON      dt.IdDiary = d.IdDiary
WHERE   userid = 1409
GROUP BY
        d.IdDay

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