我需要在PostgreSQL 9.3中编写以下查询:
- 列出每个国家/地区最受欢迎的电影。最受欢迎的电影是该国所有用户中获得最高平均评分的电影。如果打成平手,请按字母顺序返回所有电影的顺序。(2栏)
所需表:
CREATE TABLE movie (
id integer,
name varchar(200),
year date
);
CREATE TABLE userProfile (
userid varchar(200),
gender char(1),
age integer,
country varchar(200),
registered date
);
CREATE TABLE ratings (
mid integer,
userid varchar(200),
rating integer
);
CREATE INDEX movie_id_idx ON movie (id);
CREATE INDEX userProfile_userid_idx ON userProfile (userid);
CREATE INDEX ratings_userid_idx ON ratings (userid);
CREATE INDEX ratings_mid_idx ON ratings (mid);
CREATE INDEX ratings_userid_mid_idx ON ratings (userid, mid);
这是我的查询:
CREATE TEMP TABLE tops AS SELECT country, name
FROM ratings AS r INNER JOIN userProfile AS u
ON r.userid=u.userid
INNER JOIN movie AS m ON m.id = r.mid LIMIT 0;
~10 min
CREATE TEMP TABLE avg_country AS
SELECT country, r.mid, AVG(rating) AS rate
FROM ratings AS r INNER JOIN userProfile AS u
ON r.userid=u.userid
GROUP BY country, r.mid;
~8 min
DO $$
DECLARE arrow record;
BEGIN
CREATE TABLE movie_names AS SELECT id, name FROM movie;
FOR arrow IN SELECT DISTINCT country FROM userProfile ORDER BY country
LOOP
CREATE TABLE movies AS SELECT mid FROM (SELECT MAX(rate) AS m_rate FROM avg_country
WHERE country=arrow.country) AS max_val CROSS JOIN LATERAL
(SELECT mid FROM avg_country
WHERE country=arrow.country AND rate=max_val.m_rate) AS a;
WITH names AS (DELETE FROM movie_names AS m
WHERE m.id IN (SELECT mid FROM movies) RETURNING name)
INSERT INTO tops
SELECT arrow.country, name FROM names ORDER BY name;
DROP TABLE movies;
END LOOP;
DROP TABLE movie_names;
END$$;
SELECT * FROM tops;
DROP TABLE tops, avg_country;
非常感谢)
这类似于kordirko
s的答案,但子查询少了一个:
select country, movie_name, avg_rating
from (select u.country, m.name as movie_name, avg(r.rating) as avg_rating
rank() over (partition by u.country order by avg(r.rating) desc) as seqnum
from userProfile u join
ratings r
on u.userid = r.userid join
movie m
on r.mid = m.id
group by u.country, m.id -- `name` is not needed here because id is unique
) uc
where seqnum = 1;
另外,如果您想将每个国家/地区的清单都排成一列,请执行以下操作:
select country, string_agg(movie_name, '; ') as most_popular_movies
from (select u.country, m.name as movie_name, avg(r.rating) as avg_rating
rank() over (partition by u.country order by avg(r.rating) desc) as seqnum
from userProfile u join
ratings r
on u.userid = r.userid join
movie m
on r.mid = m.id
group by u.country, m.id -- `name` is not needed here because id is unique
) uc
where seqnum = 1
group by country;
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我来说两句