制作一个打印给定数字倍数的数组

Jordon 发表于 Dev

乔登

我需要帮助制作一个可以打印出给定数字的倍数的数组。输出如下：

Enter a positive integer: 8
Test array: 1 1 2 3 5 8 13
Counting up: 1 2 3 4 5 6 7 8
Counting down: 8 7 6 5 4 3 2 1
The first 8 multiples of 5: 5 10 15 20 25 30 35 40
The first 8 multiples of 10: 10 20 30 40 50 60 70 80

这是我到目前为止的代码：

//Creates an array that counts up to the user input
public static int[] countUp(int n){
    int [] temp = new int[n];
    for(int i=0; i<n; i++){
        temp[i] = i+1;
    }
    return temp;
}

//Creates an array that counts down to the user input
public static int[] countDown(int n){
    int [] temp = new int[n];
    for(int i=0; i<temp.length; i++){
        temp[i] = n--;
    }
    return temp;
}

//Creates an array that gets n amount of multiples of 5
public static int[] getMultiplesOfFive(int n){
    int [] temp = new int[n];
    for(int i=0; i<temp.length; i++){
        temp[i] = n+5;
    }
    return temp;
}

//Creates an array that gets n amount of multiples of 10
public static int[] getMultiplesOfTen(int n){
    int [] temp = new int[n];
    for(int i=0; i<temp.length; i++){
        temp[i] = n+10;
    }
    return temp;
}
}

但是我的输出看起来像这样：

Enter a positive integer: 8
Test array: 1 1 2 3 5 8 13 
Counting up: 1 2 3 4 5 6 7 8 
Counting down: 8 7 6 5 4 3 2 1 
The first 8 multiples of 5: 13 13 13 13 13 13 13 13 
The first 8 multiples of 10: 18 18 18 18 18 18 18 18

显然问题出在最后两个名为getMultiplesofFive和getMultiplesofTen的数组中。我只是不确定如何创建一个循环给我正确的输出。太感谢了！

斑鸠

在您的乘法方法中，您没有进行乘法。试试这个：

    //Creates an array that gets n amount of multiples of 5
    public static int[] getMultiplesOfFive(int n){
        int [] temp = new int[n];
        for(int i=0; i<temp.length; i++){
            temp[i] = (i+1)*10;
        }
        return temp;
    }

    //Creates an array that gets n amount of multiples of 10
    public static int[] getMultiplesOfTen(int n){
        int [] temp = new int[n];
        for(int i=0; i<temp.length; i++){
            temp[i] = (i+1)*10;
        }
        return temp;
    }