Spring REST模拟上下文路径

Georg Heiler 发表于 Dev

乔治·海勒

我尝试使用以下代码段设置spring rest模拟的上下文路径：

private MockMvc mockMvc;

@Before
public void setUp() {
    this.mockMvc = MockMvcBuilders.webAppContextSetup(this.context)
            .apply(documentationConfiguration(this.restDocumentation))
            .alwaysDo(document("{method-name}/{step}/",
                    preprocessRequest(prettyPrint()),
                    preprocessResponse(prettyPrint())))
            .build();
}

@Test
public void index() throws Exception {
    this.mockMvc.perform(get("/").contextPath("/api").accept(MediaTypes.HAL_JSON))
            .andExpect(status().isOk())
            .andExpect(jsonPath("_links.business-cases", is(notNullValue())));
}

但是我收到以下错误：

java.lang.IllegalArgumentException: requestURI [/] does not start with contextPath [/api]

怎么了？ 是否可以在代码的单个位置（例如直接在构建器中）指定contextPath？

编辑

这里的控制器

@RestController
@RequestMapping(value = "/business-case", produces = MediaType.APPLICATION_JSON_VALUE)
public class BusinessCaseController {
    private static final Logger LOG = LoggerFactory.getLogger(BusinessCaseController.class);

    private final BusinessCaseService businessCaseService;

    @Autowired
    public BusinessCaseController(BusinessCaseService businessCaseService) {
        this.businessCaseService = businessCaseService;
    }

    @Transactional(rollbackFor = Throwable.class, readOnly = true)
    @RequestMapping(value = "/{businessCaseId}", method = RequestMethod.GET)
    public BusinessCaseDTO getBusinessCase(@PathVariable("businessCaseId") Integer businessCaseId) {
        LOG.info("GET business-case for " + businessCaseId);
        return businessCaseService.findOne(businessCaseId);
    }
}

安迪·威尔金森

您需要在传递到的路径中包括上下文路径get。

在问题中显示的情况下，上下文路径为/api并且您想向其发出请求，/因此您需要传递/api/给get：

@Test
public void index() throws Exception {
    this.mockMvc.perform(get("/api/").contextPath("/api").accept(MediaTypes.HAL_JSON))
            .andExpect(status().isOk())
            .andExpect(jsonPath("_links.business-cases", is(notNullValue())));
}

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