从工厂返回$ http Promise时未定义

user3417966 发表于 Dev

用户名

无论我做什么，我总是从工厂API调用中获取$$state或undefined返回。我已经尝试过Promise，只是response.data从中返回.then但我没有尝试过。

我能得到正确的响应数据到我的控制器，但后来当我试图把它分配给什么，我只是得到undefined或者$$state，取决于哪种方法我使用。

我的工厂：

factory('forecastFactory', function ($http, $q, SundialConfig) {
    var Forecast = {}; 
    var weatherKey = SundialConfig.openWeatherKey;

    Forecast.dayCnt = 1; 
    Forecast.prepareCity = function (city) {
        city === undefined ? city = 'Chicago, IL' : city = city;
        return city; 
    }

    Forecast.getForecast = function (city) {
        var preparedCity = Forecast.prepareCity(city);
        var deferred = $q.defer();

        $http.jsonp('http://api.openweathermap.org/data/2.5/forecast/daily?', {
            params: {
                appid: weatherKey,
                q: preparedCity,
                cnt: Forecast.dayCnt,   
                callback: 'JSON_CALLBACK'
            }
        })
        .then(function (res) {
            console.log("success");
            deferred.resolve(res);
        })
        .catch(function (err) {
            console.log('error');
        });

        return deferred.promise; 
    }

    return Forecast;
});

我的控制器：

controller('ForecastController', function ($scope, $location, forecastFactory, locationService) { 
    vm = this; 
    forecastFactory.getForecast('Chicago, IL').then(function (res) {
        console.log(res);
        vm.forecast = res; 
    });
});

佐伊卜·伊亚兹（Zohaib Ijaz）

我认为您不需要使用，$q因为$ http返回了promise，

你可以做

Forecast.getForecast = function(city) {
        var preparedCity = Forecast.prepareCity(city);
        return $http.jsonp('http://api.openweathermap.org/data/2.5/forecast/daily?', {
            params: {
                appid: weatherKey,
                q: preparedCity,
                cnt: Forecast.dayCnt,   
                callback: 'JSON_CALLBACK'
            }
        })
        .then(function(res) {
      console.log("success");
      return res.data;

    })

    .catch(function(err) {
      console.log('error')
      return []; // or {} depending upon required data
    });
    }

在控制器中，执行与现在相同的操作

另一种方法是简单地返回$ http返回的promise

Forecast.getForecast = function(city) {
        var preparedCity = Forecast.prepareCity(city);

        return $http.jsonp('http://api.openweathermap.org/data/2.5/forecast/daily?', {
            params: {
                appid: weatherKey,
                q: preparedCity,
                cnt: Forecast.dayCnt,   
                callback: 'JSON_CALLBACK'
            }
        }) 
    }

并在控制器中执行此操作

Sundial.Controllers.

controller('ForecastController', ['$scope', '$location', 'forecastFactory', 'locationService', function($scope, $location, forecastFactory, locationService) { 

    vm = this; 

    forecastFactory.getForecast('Chicago, IL').then(function(res) {
        console.log(res)
        vm.forecast = res.data; 
    }, function(err){
          // do something
     })

}]);

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