我有一个切换问题，我编写了一个函数，当我将鼠标悬停在某个图像上时，该图像被更改，然后单击，然后div将显示，其他图像的显示效果与click:hover选择之前相同。
这是HTML代码
<div class="bs-example" data-example-id="simple-thumbnails">
<div class="row">
<div class="col-xs-6 col-md-4 thumbnail">
<img class="intro_ezer"
src="/img/intro_ezer_main.png"
data-holder-rendered="true"display:block;">
</div>
<div class="col-xs-6 col-md-4 thumbnail">
<img class="intro_coloris"
src="/img/intro_coloris_main.png"
data-holder-rendered="true"display:block;">
</div>
<div class="col-xs-6 col-md-4 thumbnail">
<img class="intro_galaxia"
src="/img/intro_galaxia_main.png"
data-holder-rendered="true"display:block;">
</div>
</div>
<div class="row">
<div class="col-xs-12 col-md-3 intro_ezer_detail intro">
<img class="intro_margot_main"
src="/img/intro_ezer.jpg">
</div>
<div class="col-xs-12 col-md-3 intro_coloris_detail intro">
<img class="intro_nanobuble"
src="/img/intro_ezer.jpg">
</div>
<div class="col-xs-12 col-md-3 intro_galaxia_detail intro">
<img class="intro_teatoxy"
src="/img/intro_ezer.jpg">
</div>
</div>
<div class="row">
<div class="col-xs-6 col-md-4">
<img
class="intro_margot" src="/img/intro_margot_main.png"
data-holder-rendered="true"display:block;">
</div>
<div class="col-xs-6 col-md-4">
<img
class="intro_nanobuble"
src="/img/intro_nanobuble_main.png"
data-holder-rendered="true"display:block;">
</div>
<div class="col-xs-6 col-md-4">
<img class="intro_teatoxy"
src="/img/intro_teatoxy_main.png"
data-holder-rendered="true"display:block;">
</div>
</div>
<div class="row detail">
<div class="col-xs-12 col-md-3 intro">
<img src="/img/intro_ezer.jpg">
</div>
<div class="col-xs-12 col-md-3 intro_nanobuble_detail intro">
<img src="/img/intro_ezer.jpg">
</div>
<div class="col-xs-12 col-md-3 intro_teatoxy_detail intro">
<img src="/img/intro_ezer.jpg">
</div>
</div>
</div>
javascript
var className = "";
var toggleImg = "";
$('div').find('img').hover(function() {
className = $(this).attr('class');
this.src = '/img/' + className + '_hover.png';
}, function() {
this.src = '/img/' + className + '_main.png';
}).click(function(e) {
toggleImg = className + "_detail";
e.preventDefault(); $('.intro').hide()
$("."+className+"_detail").show();
})
我能怎么做？
您应该使用.each
检查以下示例。
HTML：
<div>
<img alt="chrome" src="https://lh3.ggpht.com/O0aW5qsyCkR2i7Bu-jUU1b5BWA_NygJ6ui4MgaAvL7gfqvVWqkOBscDaq4pn-vkwByUx=w300">
</div>
<div>
<img alt="firefox" src="https://www.mozilla.org/media/img/firefox/firefox-256.e2c1fc556816.jpg">
</div>
JS：
$('div img').each(function() {
$(this).click(function() {
alert($(this).attr('alt'));
});
});
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我来说两句