使用PHP和JIRA REST API,我可以通过以下代码将观察者添加到现有问题中:
$username = 'xxxx';
$password = 'xxxx';
$proxy = 'http://xxxx:8080/';
$url = "http://xxxx/rest/api/2/issue/xxxx/watchers";
$data = 'name1';
$ch = curl_init();
$headers = array(
'Accept: application/json',
'Content-Type: application/json'
);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_VERBOSE, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode($data));
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_PROXY, $proxy);
curl_setopt($ch, CURLOPT_USERPWD, "$username:$password");
$result = curl_exec($ch);
$ch_error = curl_error($ch);
if ($ch_error) {
echo "cURL Error: $ch_error";
} else {
echo $result;
}
curl_close($ch);
但是,此方法仅允许我添加一个观察者。是否可以将多个观察者添加到现有问题?我尝试过这种方式:
$data = array(
'name1',
'name2',
);
但这会导致错误的请求错误。
因此,我能解决这个问题的唯一方法是只进行多个API调用来添加观察者。由于某些原因,该API无法接受具有多个名称的格式正确的JSON调用。如果仅是一个名称,则JSON输出为just "name1"
,但是对于数组中的多个名称,它将变为["name1","name2","name3"]
(方括号显然是将其丢弃的原因)。
如果有人知道更好的方法,请告诉我,但这是我最终要做的事情(尽管如此,我确实认为这是一种解决方法,而不是答案):
$username = 'xxxx';
$password = 'xxxx';
$proxy = 'http://xxxx:8080/';
$url = "http://xxxx/rest/api/2/issue/xxxx/watchers";
$data = array(
'name1',
'name2',
'name3'
);
$headers = array(
'Accept: application/json',
'Content-Type: application/json'
);
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_VERBOSE, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_PROXY, $proxy);
curl_setopt($ch, CURLOPT_USERPWD, "$username:$password");
foreach ($data as $key => $user)
{
curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode($user));
$result = curl_exec($ch);
}
curl_close($ch);
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