我想像这样回显JSON数组对象的每个元素：
{"request_list":[{"id":"1","name":"yunus","surname":"smsk","phone_number":"05350601922","blood_type":"0","unit_of_blood":"0","date":null},{"id":"3","name":"yunus","surname":"smsk","phone_number":"05350601922","blood_type":"0","unit_of_blood":"0","date":null}]}
但是我做不到，我尝试过这样的事情：
$object = json_decode($json, true);
$request_list = $object->request_list;
foreach($request_list as $r){
echo $r->name;
echo $r->blood_type;
echo $r->phone_number;
}
但是我遇到了类似的错误：
为foreach（）提供了无效的参数
当您在中将标记返回为数组true时json_decode。因此，请尝试以下代码。
$object = json_decode($json, true);
$request_list = $object['request_list'];
foreach($request_list as $r){
echo $r['name'];
echo $r['blood_type'];
echo $r['phone_number'];
}
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我来说两句