在csv文件中，我在下面的列中，尝试用更改第二列的值
awk -F ',' -v OFS=',' '$1 { $2=$2*2; print}' path/file.csv > output.csv。
但是它返回零并删除双引号。
file.csv
"sku","0.47","supplierName"
"sku","3.14","supplierName"
"sku","3.56","supplierName"
"sku","4.20","supplierName"
output.csv
"sku",0,"supplierName"
"sku",0,"supplierName"
"sku",0,"supplierName"
"sku",0,"supplierName"
您可以在FS值中指定多个字符。
$ awk -v FS="\",\"" -v OFS="\",\"" '{$2=$2*2}1' file
"sku","0.94","supplierName"
"sku","6.28","supplierName"
"sku","7.12","supplierName"
"sku","8.4","supplierName"
如果要四舍五入到小数点后两位，请尝试此操作。
$ awk -v FS="\",\"" -v OFS="\",\"" '{$2=sprintf("%.2f",$2*2)}1' file
"sku","0.94","supplierName"
"sku","6.28","supplierName"
"sku","7.12","supplierName"
"sku","8.40","supplierName"
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我来说两句