我试图创建一个主要使用Spring访问REST API的应用程序,并试图配置安全性。尝试使用此图片展示应用程序的实际结构:
我试图创建一个基本结构,但我认为必须犯一个小错误,因为它无法按预期运行。
@Configuration
@EnableWebSecurity
@EnableWebMvcSecurity
@EnableGlobalMethodSecurity(securedEnabled=true, prePostEnabled=true)
public class UserDetailsSecurityConfig extends WebSecurityConfigurerAdapter {
@Autowired
private NSecurityContextHolder securityContextHolder;
@Autowired
private NHttpServletRequestBinder<Authentication> authenticationBinder;
public static final String DEF_USERS_BY_USERNAME_QUERY
= "SELECT user ";
public static final String GROUPS_BY_USERNAME_QUERY =
"SELECT groups by user";
public static final String DEF_GROUP_AUTHORITIES_BY_USERNAME_QUERY =
"SELECT authorities";
@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
auth.jdbcAuthentication().dataSource(getDataSourceFromJndi())
.usersByUsernameQuery(DEF_USERS_BY_USERNAME_QUERY).
authoritiesByUsernameQuery(DEF_GROUP_AUTHORITIES_BY_USERNAME_QUERY).
groupAuthoritiesByUsername(GROUPS_BY_USERNAME_QUERY);
}
private DataSource getDataSourceFromJndi() {
try {
DataSource dataSource = (DataSource) new InitialContext().lookup("DS");
return dataSource;
} catch (Exception e) {
e.printStackTrace();
return null;
}
}
@Bean
@Override
public AuthenticationManager authenticationManagerBean() throws Exception {
return super.authenticationManagerBean();
}
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.jdbcAuthentication().dataSource(getDataSourceFromJndi())
.usersByUsernameQuery(DEF_USERS_BY_USERNAME_QUERY).
authoritiesByUsernameQuery(DEF_GROUP_AUTHORITIES_BY_USERNAME_QUERY).
groupAuthoritiesByUsername(GROUPS_BY_USERNAME_QUERY);
}
@Override
protected void configure(HttpSecurity http) throws Exception {
// The http.formLogin().defaultSuccessUrl("/path/") method is required when using stateless Spring Security
// because the session cannot be used to redirect to the page that was requested while signed out. Unfortunately
// using this configuration method will cause our custom success handler (below) to be overridden with the
// default success handler. So to replicate the defaultSuccessUrl("/path/") configuration we will instead
// correctly configure and delegate to the default success handler.
final SimpleUrlAuthenticationSuccessHandler delegate = new SimpleUrlAuthenticationSuccessHandler();
delegate.setDefaultTargetUrl("/api/");
// Make Spring Security stateless. This means no session will be created by Spring Security, nor will it use any
// previously existing session.
http.sessionManagement().sessionCreationPolicy(STATELESS);
// Disable the CSRF prevention because it requires the session, which of course is not available in a
// stateless application. It also greatly complicates the requirements for the sign in POST request.
http.csrf().disable();
// Viewing any page requires authentication.
http.authorizeRequests().anyRequest().authenticated();
http
.formLogin().loginPage("http://localhost/web/ui/#access/signin")
.permitAll()
// Override the sign in success handler with our stateless implementation. This will update the response
// with any headers and cookies that are required for subsequent authenticated requests.
.successHandler(new NStatelessAuthenticationSuccessHandler(authenticationBinder, delegate));
http.logout().logoutUrl("http://localhost/web/ui/#access/signin").logoutSuccessUrl("http://localhost/web/ui/#access/signin");
// Add our stateless authentication filter before the default sign in filter. The default sign in filter is
// still used for the initial sign in, but if a user is authenticated we need to acknowledge this before it is
// reached.
http.addFilterBefore(
new StatelessAuthenticationFilter(authenticationBinder, securityContextHolder),
UsernamePasswordAuthenticationFilter.class
);
}
}
我有两种身份验证绑定程序,即TokenBased和UserNameBased。
基于令牌:
@Component
public class NXAuthTokenHttpServletRequestBinder implements NHttpServletRequestBinder<String> {
private static final String X_AUTH_TOKEN = "X-AUTH-TOKEN";
private final NTokenFactory tokenFactory;
@Autowired
public NXAuthTokenHttpServletRequestBinder(NTokenFactory tokenFactory) {
this.tokenFactory = tokenFactory;
}
@Override
public void add(HttpServletResponse response, String username) {
final String token = tokenFactory.create(username);
response.addHeader(X_AUTH_TOKEN, token);
response.addCookie(new Cookie(X_AUTH_TOKEN, token));
}
@Override
public String retrieve(HttpServletRequest request) {
final String cookieToken = findToken(request);
if (cookieToken != null) {
return tokenFactory.parseUsername(cookieToken);
}
return null;
}
private static String findToken(HttpServletRequest request) {
Enumeration<String> it = request.getHeaderNames();
while(it.hasMoreElements()){
System.out.println(it.nextElement());
}
final String headerToken = request.getHeader(X_AUTH_TOKEN);
if (headerToken != null) {
return headerToken;
}
final Cookie[] cookies = request.getCookies();
if (cookies != null) {
for (Cookie cookie : cookies) {
if (X_AUTH_TOKEN.equals(cookie.getName())) {
return cookie.getValue();
}
}
}
return null;
}
}
基于用户:
@Component
@Primary
public class NUserAuthenticationFactory implements NHttpServletRequestBinder<Authentication> {
private final NHttpServletRequestBinder<String> httpServletRequestBinder;
@Autowired
public NUserAuthenticationFactory(NHttpServletRequestBinder<String> httpServletRequestBinder) {
this.httpServletRequestBinder = httpServletRequestBinder;
}
@Override
public void add(HttpServletResponse response, Authentication authentication) {
httpServletRequestBinder.add(response, authentication.getName());
}
@Override
public UserAuthentication retrieve(HttpServletRequest request) {
final String username = httpServletRequestBinder.retrieve(request);
if (username != null) {
return new UserAuthentication(new CustomJDBCDaoImpl().loadUserByUsername(username));
}
return null;
}
}
问题每当我加载我的应用程序时,它都会进入基于用户的身份验证,然后尝试从令牌中获取用户名,而不是从数据库中进行验证。但是,到那时,还没有令牌,因为这是我从UI发出的第一个发布请求。然后将我重定向回同一登录页面。
日志:
精细:/位于附加过滤器链中12的位置1;触发过滤器:'WebAsyncManagerIntegrationFilter'精细:/在附加过滤器链中12的位置2中;触发过滤器:'SecurityContextPersistenceFilter'精细:/在附加过滤器链中12的位置3中;触发Filter:'HeaderWriterFilter'罚款:
不注入HSTS标头,因为它与requestMatcher org.springframework.security.web.header.writers.HstsHeaderWriter$SecureRequestMatcher@a837508不匹配罚款:/位于附加过滤器链中12的位置4;触发过滤器:'LogoutFilter'罚款:检查请求的匹配:'/'; 针对' http:// localhost / web / ui /#access / signin'精细:/位于附加过滤器链中12的位置5处;触发过滤器:'StatelessAuthenticationFilter'精细:/在附加过滤器链中12的位置6中;触发筛选器:'UsernamePasswordAuthenticationFilter'罚款:请求'GET /'与'POST http:// localhost / web / ui /#access / signin不匹配精细:/在附加过滤器链中的12的位置7中;触发过滤器:'RequestCacheAwareFilter'精细:/在附加过滤器链中的12的位置8;触发过滤器:'SecurityContextHolderAwareRequestFilter'精细:/位于附加过滤器链中12的位置9;触发过滤器:'AnonymousAuthenticationFilter'罚款:填充的SecurityContextHolder,带有匿名令牌:'org.springframework.security.authentication.AnonymousAuthenticationToken@9055e4a6:主体:onymousUser; 凭证:[受保护];已验证:true;详细信息:org.springframework.security.web.authentication.WebAuthenticationDetails@957e:RemoteIpAddress:127.0.0.1; SessionId:null;授予的权限:ROLE_ANONYMOUS'罚款:/位于附加过滤器链中第12个位置的10;触发筛选器:'SessionManagementFilter'罚款:请求的会话ID 3e2c15a2a427bf47e51496d2a186无效。精细:/位于附加过滤器链中12的位置11;触发过滤器:'ExceptionTranslationFilter'精细:/在附加过滤器链中12的位置12中;触发Filter:'FilterSecurityInterceptor'罚款:安全对象:FilterInvocation:URL:/; 属性:[已认证]精细:先前已认证:org.springframework.security.authentication.AnonymousAuthenticationToken@9055e4a6:主体:anonymousUser;凭证:[受保护];已验证:true;详细信息:org.springframework.security.web.authentication.WebAuthenticationDetails@957e:RemoteIpAddress:127.0.0.1; SessionId:null;授予的权限:ROLE_ANONYMOUS罚款:选民:org.springframework.security.web.access.expression.WebExpressionVoter@2ac71565,返回:-1罚款:访问被拒绝(用户是匿名的);重定向到身份验证入口点org.springframework.security.access.AccessDeniedException:访问被拒绝
逐步解决您的问题即可。
UsernamePasswordAuthenticationFilter
通过用户名和密码对用户进行身份验证并生成唯一令牌。AuthenticationProvider
实现,以验证用户的连续请求。UsernamePasswordAuthenticationFilter
如下所示放置自定义安全过滤器
http.addFilterBefore(CustomTokenBasedAuthenticationFilter,UsernamePasswordAuthenticationFilter.class);
向您注册AuthenticationProvider
实施AuthenticationManager
就是这样!!!
注意:保护其余API的更好方法是使用一些标准协议,例如oauth1a,oauth2.0等。Spring提供了oauth1a和oauth2.0协议的新颖实现。
本文收集自互联网,转载请注明来源。
如有侵权,请联系[email protected] 删除。
我来说两句