“ For循环” Oracle PL / SQL中的迭代计数

Prabha Christ 发表于 Dev

般若基督

编写PLSQL块以显示给定数字中的奇数和奇数总数？例如：如果给定数字为3，则显示如下1为奇数3为奇数3中共有2个奇数

CREATE OR REPLACE PROCEDURE odd_num(p_num NUMBER ) 
   IS s_num NUMBER;
BEGIN 
   FOR i_num IN 1..p_num  
      LOOP   
         IF mod(i_num,2) = 1 
         THEN     
            dbms_output.put_line(i_num ||' is Odd Number');  
         END IF; 
      END LOOP;  
   dbms_output.put_line('Total '|| s_num ||' Odd Numbers in '||p_num);
END;

Lalit Kumar B

您只需要初始化并将计数器分配给即可s_num。只需在IF块中添加以下内容：

s_num := s_num +1;

例如，

SQL> CREATE OR REPLACE PROCEDURE odd_num(p_num NUMBER )
  2  IS
  3  s_num NUMBER;
  4  BEGIN
  5     s_num :=0;
  6     FOR i_num IN 1..p_num
  7        LOOP
  8           IF mod(i_num,2) = 1
  9           THEN
 10              -- Increment the counter once for each iteration
 11              s_num := s_num +1;
 12              dbms_output.put_line(i_num ||' is Odd Number');
 13           END IF;
 14        END LOOP;
 15     dbms_output.put_line('Total '|| s_num ||' Odd Numbers in '||p_num);
 16  END;
 17  /

Procedure created.

SQL> sho err
No errors.

让我们执行以下过程：

SQL> SET SERVEROUTPUT ON
SQL> EXEC odd_num(5);
1 is Odd Number
3 is Odd Number
5 is Odd Number
Total 3 Odd Numbers in 5

PL/SQL procedure successfully completed.

SQL>

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