如何使用记录将JSON字符串转换为二进制？Web.Contents + POST + Power Query

Sergey Lossev 发表于 Dev

谢尔盖·洛塞夫（Sergey Lossev）

Web.Contents方法将Content作为二进制

我使用此代码。有用

query = "{
    ""field1"" : ""value1"",
    ""field2"" : ""value2"",
    ""field3"" : {
        ""sub_field_3_1"" : [""value_3_1_1"", ""value_3_1_2"", ""value_3_1_1""],
        ""sub_field_3_2"" : [""value_3_2_1"", ""value_3_2_2"", ""value_3_2_1""]
        }
    }",

content = Text.ToBinary(query),

Web.Contents("https://my_url", [
    Headers = [#"Content-Type"="text/xml; charset=utf-8"],
    Content=content
])

我知道，这不是一个好的解决方法，因为没有理由进行双重转换。但是我找不到一种方法来应用记录，它应该看起来像这样：

record = [
    field1 = value1,
    field2 = value2,
    field3 = [
        sub_field_3_1 = {value_3_1_1, value_3_1_2, value_3_1_1},
        sub_field_3_2 = {value_3_2_1, value_3_2_2, value_3_2_1}
    ]
],

content = SOME_CONVERTER(record),

Web.Contents("https://my_url", [
    Headers = [#"Content-Type"="text/xml; charset=utf-8"],
    Content = content
])

试图使用Uri.BuildQueryString（如何使用Power Query的Web.Contents来发布多部分/表单数据），但是它不能正确地形成Binary

record = [
    field1 = value1,
    field2 = value2,
    field3 = [
        sub_field_3_1 = {value_3_1_1, value_3_1_2, value_3_1_1},
        sub_field_3_2 = {value_3_2_1, value_3_2_2, value_3_2_1}
    ]
],

content = Text.ToBinary(Uri.BuildQueryString(record)),

Web.Contents("https://my_url", [
    Headers = [#"Content-Type"="text/xml; charset=utf-8"],
    Content=content
]

有更好的解决方法吗？

卡尔·沃尔什

目前，您的硬编码JSON字符串是更好的解决方案之一。

这并不理想，但是您可以使用自己的值到JSON转换功能，例如toJson：

let
    record = [
        field1 = "value1",
        field2 = "value2",
        field3 = [
            sub_field_3_1 = {"value_3_1_1", null, 3.2},
            sub_field_3_2 = {"value_3_2_1", "value_3_2_2", "value_3_2_1"}
        ]
    ],

    toJson = (v as any) as text =>
      if v is null then "null" else 
      if v is logical or v is number then Text.From(v) else
      if v is text then """" & Text.Replace(Text.Replace(v, "\", "\\"), """", "\""") & """" else
      if v is list then "[" & Text.Combine(List.Transform(v, @toJson), ", ") & "]" else
      if v is record then "{" & 
        Text.Combine(List.Transform(
          Record.FieldNames(v),
          (n) => @toJson(n) & ": " & @toJson(Record.Field(v, n))), ", ")
        & "}" else
      error "not implemented",  

    jsonText = toJson(record)
in
    jsonText