def isIncreasing(ls):
if not ls:
print "List empty or to short"
return
return (False if ls[0] > ls[1] else isIncreasing(ls[1:]))
我这样做是为了检查列表是否已排序。没有更多要检查时，如何使功能停止？
我收到错误
“列表索引超出范围”。
只需添加：
代码：
def isIncreasing(ls):
if len(ls) < 2:
print "List empty or to short"
return
if len(ls) == 2:
return ls[0] < ls[1]
return (False if ls[0] > ls[1] else isIncreasing(ls[1:]))
print "{}", isIncreasing({})
print "[]", isIncreasing([])
print [1,2,3], isIncreasing([1,2,3])
print [4,6,8], isIncreasing([4,6,8])
print [2,1,2,3], isIncreasing([2,1,2,3])
print [1,2,3,2], isIncreasing([1,2,3,2])
print [3,2,1], isIncreasing([3,2,1])
输出：
{} List empty or to short
None
[] List empty or to short
None
[1, 2, 3] True
[4, 6, 8] True
[2, 1, 2, 3] False
[1, 2, 3, 2] False
[3, 2, 1] False
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