是否可以在不向每个属性添加[JsonProperty]属性的情况下使用JSON.NET序列化静态属性。示例类:
public class Settings
{
public static int IntSetting { get; set; }
public static string StrSetting { get; set; }
static Settings()
{
IntSetting = 5;
StrSetting = "Test str";
}
}
预期结果:
{
"IntSetting": 5,
"StrSetting": "Test str"
}
默认行为跳过静态属性:
var x = JsonConvert.SerializeObject(new Settings(), Formatting.Indented);
您可以使用自定义合同解析器执行此操作。具体来说,您需要继承DefaultContractResolver
并重写该GetSerializableMembers
函数:
public class StaticPropertyContractResolver : DefaultContractResolver
{
protected override List<MemberInfo> GetSerializableMembers(Type objectType)
{
var baseMembers = base.GetSerializableMembers(objectType);
PropertyInfo[] staticMembers =
objectType.GetProperties(BindingFlags.Static | BindingFlags.Public);
baseMembers.AddRange(staticMembers);
return baseMembers;
}
}
在这里,我们要做的是调用的基本实现GetSerializableMembers
,然后将public static
属性添加到要序列化的成员列表中。
要使用它,您可以创建一个新JsonSerializerSettings
对象并将设置ContractResolver
为的实例StaticPropertyContractResolver
:
var serializerSettings = new JsonSerializerSettings();
serializerSettings.ContractResolver = new StaticPropertyContractResolver();
现在,将这些设置传递到JsonConvert.SerializeObject
,一切都将正常工作:
string json = JsonConvert.SerializeObject(new Settings(), serializerSettings);
输出:
{
"IntSetting": 5,
"StrSetting": "Test str"
}
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