使用PHP将数据插入多个表

iYoue 发表于 Dev

iYoue

我正在尝试使用PHP将数据添加到2个表中

我的PHP代码：insert.php

<?php
session_start();
$db['host'] = "dbhost";
$db['user'] = "user";
$db['pass'] = "pass";
$db['name'] = "dbname";

//making an array with the data recieved
$data = array('f_name' => $_POST['txt_f_name'],
              'l_name' => $_POST['txt_l_name'],
              'VNum' => $_POST['txtVisaNo']);

try {
    // preparing database handle $dbh
    $dbh = new PDO("mysql:host=".$db['host']."; dbname=".$db['name']."", $db['user'], $db['pass']);
    // set the PDO error mode to exception
    $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$insertall = "BEGIN; "
        . "INSERT INTO students (f_name, l_name) "
        . "VALUES (:f_name, :l_name); "
        . "INSERT INTO visa (students_id, VNum) "
        . "VALUES (:LAST_INSERT_ID(), :VNum); "
        . "$addStdInf->execute($data); "
        . "COMMIT;";
$addStdInf = $dbh->prepare($insertall);

echo 'Success!';
}
catch(PDOException $e){
    echo $sql,'<br />', $e->getMessage();

}
$dbh = null;
?>

通知是“成功！” 但是它什么也没插入数据库，请指导我出现错误。谢谢。

贾加迪什

您忘记执行pdo语句

<?php
session_start();
$db['host'] = "dbhost";
$db['user'] = "user";
$db['pass'] = "pass";
$db['name'] = "dbname";

//making an array with the data recieved
$data = array('f_name' => $_POST['txt_f_name'],
              'l_name' => $_POST['txt_l_name'],
              'VNum' => $_POST['txtVisaNo']);

try {
    // preparing database handle $dbh
    $dbh = new PDO("mysql:host=".$db['host']."; dbname=".$db['name']."", $db['user'], $db['pass']);
    // set the PDO error mode to exception
    $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$insertall = "BEGIN; "
        . "INSERT INTO students (f_name, l_name) "
        . "VALUES (:f_name, :l_name); "
        . "INSERT INTO visa (students_id, VNum) "
        . "VALUES (:LAST_INSERT_ID(), :VNum); "
        . "$addStdInf->execute($data); "
        . "COMMIT;";
$addStdInf = $dbh->prepare($insertall);
$result = $addStdInf->execute();
if ($result) {
    echo 'Success!'; 
} else {
    echo 'please check';
}
}
catch(PDOException $e){
    echo $sql,'<br />', $e->getMessage();

}
$dbh = null;
?>