如何在R中以水平堆积条形图的样式创建时间序列图

jjulip 发表于 Dev

朱利普

我想创建一个水平的“堆积条形”类型图，其中日期沿x轴运行，而我的样本在y轴上显示为条形。在下面的简单示例中，我有三个样本（a，b，c），每个样本都包含三个值（0、1、2）。我希望根据沿x轴每个时间步长的值对水平条进行着色，以便最终得到从我的第一个时间点到最后一个时间点延伸的三个水平条（每个样本一个），并包含一个与不同值相关的颜色的一系列块。

例如，假设我希望值0为蓝色，值1为黄色，值2为红色：对于样品a，迹线的前两天将是蓝色，然后第二天将是黄色，然后是单个蓝色等等……

示例数据：

df <- structure(list(date = c("30/04/2011", "01/05/2011", "02/05/2011", "03/05/2011", "04/05/2011", "05/05/2011", "06/05/2011", "07/05/2011", "08/05/2011", "09/05/2011", "10/05/2011", "11/05/2011", "12/05/2011", "13/05/2011", "14/05/2011", "15/05/2011", "16/05/2011", "17/05/2011", "18/05/2011", "19/05/2011", "20/05/2011", "21/05/2011", "22/05/2011", "23/05/2011", "24/05/2011", "25/05/2011", "26/05/2011", "27/05/2011", "28/05/2011", "29/05/2011", "30/05/2011", "31/05/2011", "01/06/2011", "02/06/2011", "03/06/2011", "04/06/2011", "05/06/2011", "06/06/2011", "07/06/2011", "08/06/2011", "09/06/2011", "10/06/2011", "11/06/2011", "12/06/2011", "13/06/2011", "14/06/2011", "15/06/2011", "16/06/2011", "17/06/2011", "18/06/2011", "19/06/2011", "20/06/2011", "21/06/2011", "22/06/2011", "23/06/2011", "24/06/2011", "25/06/2011", "26/06/2011", "27/06/2011", "28/06/2011", "29/06/2011", "30/06/2011", "01/07/2011", "02/07/2011", "03/07/2011", "04/07/2011", "05/07/2011", "06/07/2011", "07/07/2011", "08/07/2011", "09/07/2011", "10/07/2011", "11/07/2011", "12/07/2011", "13/07/2011", "14/07/2011", "15/07/2011", "16/07/2011", "17/07/2011", "18/07/2011", "19/07/2011", "20/07/2011", "21/07/2011", "22/07/2011", "23/07/2011", "24/07/2011"), a = c(0L, 0L, 1L, 1L, 0L, 1L, 0L, 0L, 0L, 1L, 0L, 0L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L, 1L, 0L, 0L, 0L, 1L, 1L, 0L, 0L, 0L, 1L, 1L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L), b = c(0L, 1L, 1L, 0L, 0L, 0L, 0L, 1L, 1L, 0L, 0L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 0L, 0L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L, 1L, 1L), c = c(1L, 1L, 0L, 0L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L, 0L, 0L, 0L, 0L)), .Names = c("date", "a", "b", "c"), class = "data.frame", row.names = c(NA, -86L))

head(df)
#         date a b c
# 1 30/04/2011 0 0 1
# 2 01/05/2011 0 1 1
# 3 02/05/2011 1 1 0
# 4 03/05/2011 1 0 0
# 5 04/05/2011 0 0 0

这一定是很容易实现的事情，但我无法理解（例如，条形图似乎对此不起作用）。任何帮助，将不胜感激。谢谢！

G.格洛腾迪克

对于ggplot2图，首先将df转换为长格式（使用reshape2包中的melt），将date列转换为"Date"class并将value列转换为因数，然后使用geom_tile：

library(ggplot2)
library(reshape2)

long <- melt(df, measure.var = 2:4)
long <- transform(long, date = as.Date(long$date, "%d/%m/%Y"), value = factor(value))

ggplot(long, aes(date, variable)) + 
   geom_tile(aes(fill = value)) + 
   scale_fill_manual(values = c("blue", "yellow", "red"))